classSolution:defcanMeasureWater(self, x:int, y:int, z:int) ->bool:# solution one: BFSfromcollectionsimportdeque queue = deque([[0,0]]) visited =set([(0,0)])whilequeue: cur_x, cur_y = queue.pop()ifzin[cur_x, cur_y, cur_x + cur_y]:returnTrueforitemin[# x 加满水,y 加...
学习leetcode_365: Water and Jug Problem的解法:辗转相除相关内容(最大公约数、裴蜀定理、欧几里得算法和扩展欧几里得算法)。 正文: 1、问题描述 You are given two jugs with capacitiesxandylitres. There is an infinite amount of water supply available. You need to determine whether it is possible to m...
(jug2_capacity,jug1+jug2))# Pour jug1 into jug2]foractioninactions:ifactionnotinvisited:visited.add(action)queue.append((action,path+[action]))returnNone# Example usagejug1_capacity=4jug2_capacity=3target=2path=water_jug_problem_trace_path(jug1_capacity,jug2_capacity,target)ifpath:print(...
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Graph Water Jug problem using BFS <-> Graph Find if there is a path of more thank length from a source <-> Graph M-ColouringProblem <-> Graph Minimum edges to reverse o make path from source to destination <-> Graph Paths to travel each nodes using each edge(Seven Bridges) <-> ...