# Program to check if a number is prime or not# Input from the usernum =int(input("Enter a number: "))# If number is greater than 1ifnum >1:# Check if factor existforiinrange(2,num):if(num % i) ==0:print(num,"is not a prime number")breakelse:print(num,"is a prime nu...
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# Program to check if a number is prime or not num = 29 # To take input from the user #num = int(input("Enter a number: ")) # define a flag variable flag = False if num == 0 or num == 1: print(num, "is not a prime number") elif num > 1: # check for factors for...
import mathimport timedefis_prime(num):if num == 2: returnTrueif num <= 1ornot num % 2: returnFalsefor div in range(3, int(math.sqrt(num) + 1), 2): ifnot num % div: returnFalsereturnTruedefrun_program(N): total = 0for i in range(N): if is_prime(i)...
foriinrange(2,n): ifn%i0: returnFalse else: returnTrue Foriinrange(2,100+1): ifprime(i)Trueandprime(i+2)True: print(({:^4},{:^4}).format(i,i+2)) 解析: 82.[问答题](填空题)表达式{1,2,3}|{3,4,5}的值为___。 答案:{1...
i wrote this program to check weather the no. is prime or not but it shows the number is prime multiple times. how can i solve it To check weather the number is prime or not. num = int(input("please enter the number you want to check\n")) if num > 1: for i in range(2, ...
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say say not pepsi or pepsi 1. 2. 3. 4. def print_strings(s, n): for i in range(1, n + 1): print(s, end=" ") print() 1. 2. 3. 4. The program changes the value of its parameter on line 9, but this doesn't affect the variable in . The (incorrect) output is:Temper...
If none of the calculations lead to 0, you find a prime (and thus print it) En your second example: For each number, do a modulo calculation and break if it leads to 0 If it doesn't lead to 0: print the number. Which happens quite more often than the else in example 1. Sh...
def is_prime(num): if num == 2: return True if num <= 1 or not num % 2: return False for div in range(3, int(math.sqrt(num) + 1), 2): if not num % div: return False return True def run_program(N): total = 0 ...