defis_armstrong_number(num):# 将数字转换为字符串以便逐位计算digits=str(num)num_digits=len(digits)# 计算每位数字的 num_digits 次幂的和sum_of_powers=sum(int(digit)**num_digitsfordigitindigits)returnsum_of_powers==numdeffind_all_armstrong_numbers(start,end):armstrong_numbers=[]fornuminrange(s...
以下是Python实现水仙花数的流程图: ProgramUserProgramUser调用 find_armstrong_numbers(1, 10000)for循环遍历1到10000调用 is_armstrong_number(num)计算位数及n次幂之和sum_of_powers如果 sum_of_powers == num返回水仙花数 结论 水仙花数是数字趣味性和计算能力相结合的完美示例。通过Python编程,我们不仅可以快速统...
In this Python article, you learnedHow to Find Armstrong Number Using Recursion in Pythonwith the practical example where we are taking user input to make the program dynamic. You may also like to read: Bijay Kumar I am Bijay Kumar, aMicrosoft MVPin SharePoint. Apart from SharePoint, I st...
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Enter a number: 0 Zero A number is positive if it is greater than zero. We check this in the expression of if. If it is False, the number will either be zero or negative. This is also tested in subsequent expression.Also Read: Python Program to Check if a Number is Odd or Even ...
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The output of Leap Year Program In Python: 2024 is a leap year. Also Read: How to check for Armstrong Number in Python? Different Methods to Find Leap Year In Python Programming There are a lot of different methods to find the leap year in the Python Program. Here are a few: i)...
num = int(input("Enter the number:\n")) order = len(str(num)) sum = 0 temp = num while temp > 0: digit = temp % 10 sum += digit ** order temp //= 10 if num == sum: print(num,"is an Armstrong number") else: print(num,"is not an Armstrong number")...
if num == sum: print(num,"is an Armstrong number")else: print(num,"is not an Armstrong number")▍50、用一行Python代码,从给定列表中取出所有的偶数和奇数a = [1,2,3,4,5,6,7,8,9,10]odd, even = [el for el in a if el % 2==1...
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