Python Leap Year #The test case is passing 4/6. I don't know what is wrong with my code, please help year = int(input()) if year % 4 == 0: if year % 100 == 0: if year % 400 == 0: print("Leap year") else: print("Not a leap year") else: print("Not a leap year...
6.程序实现的功能:输入某年某月某日,判断这一天是这一年的第几天,Python代码如下def leap(year):leap=0if(year%400==0)or((year%4==0)and(year%100!=0)leap=1①y=int(input("请输入年份:"))m=int(input("请输人月份:"))d=int(input("请输入日:"))months=(0,31,59,90,120,151,181,212,...
For example, 2017 is not a leap year 1900 is a not leap year 2012 is a leap year 2000 is a leap year Source Code # Python program to check if year is a leap year or not year = 2000 # To get year (integer input) from the user # year = int(input("Enter a year: ")) #...
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1 TypeError: is_leap_year() takes 0 positional arguments but 1 was given 问题分析: 报错的意思是:is_leap_year()这个函数不需要参数,但是函数却被传递了一个参数。 掉头检查代码,会发现: 1 def is_leap_year(): 这里出了问题,我们对其进行修改: 1 def is_leap_year(year): 再次运行代码,成功...
= 0 instead of == 0 to output a print command. Here's what I came up with. I didn't see that step 2 said "IS a leap year" which stumped me for a while. year = int(input()) #your code goes here if year % 4 != 0: print("Not a leap year") elif year % 100 != 0:...
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("Invalidinput.Pleaseentervalidnumericalvaluesforcoordinates.")if__name__=="__main__":main()2.编写程序,从键盘输入年份值和月份值,输出该年当月的日历(调用calendar模块中的month()函数)。答案:importcalendardefmain():try:year=int(input("Entertheyear:"))month=int(input("Enterthemonth(1-12):")...
经典题目:输入年份判断闰年 year = int(input('请输入年份')) leap_year = year % 4 == 0 && year % 100 != 0 || year % 400 == 0 print(leap_year) 输入:2000 结果:True 三、分支结构 在python中分支结构使用if-elif-else 代码语言:javascript 复制 题目:百分制成绩转换为等级制成绩如果输入...
if is_leap(data): print("是闰年") else: print("不是闰年") 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 1.2 定义一个函数cubic(n),该函数返回1~n的立方和。 def cubic(n): sum = 0; for i in range(0,n): sum = sum + i**2 ...