odd_numbers = [num for num in arr if num % 2 != 0] print(odd_numbers) ``` 3. 使用 `filter()` 函数结合 `lambda` 表达式: ```python arr = [1, 2, 3, 4, 5, 6, 7, 8, 9] odd_numbers = list(filter(lambda x: x % 2 != 0, arr)) print(odd_numbers) ``` 这些方法都...
So the final output of this code will be a new list containing only the odd numbers from the original list, i.e., [7, 25, 27]. Flowchart: Even Numbers between 1 to 100: Python Code Editor: Previous:Write a Python program to generate a 3*4*6 3D array whose each element is *. ...
元素的值进行分组创建多个列表 numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] odd_numbers = [] even_numbers = [] for num in numbers: if num % 2 == 0: even_numbers.append(num) else: odd_numbers.append(num) print("奇数列表:", odd_numbers) print("偶数列表:", even_numbers)...
even_numbers = filter(is_even, numbers) print(list(even_numbers)) # [2, 4] 示例:2 numbers = [1, 2, 3, 4, 5] # iterable def is_odd(num): if num % 2 != 0: return True return False odd_numbers = filter(is_odd, numbers) print(list(odd_numbers)) # [1, 3, 5] # Filte...
Here, you have three integer numbers: a positive one, a negative one, and zero. Note that to create negative integers, you need to prepend the minus sign (-) to the number.Python has no limit to how long an integer value can be. The only constraint is the amount of memory your ...
sum() Prob_C = N_odd_number/one_million_tosses.shape[0] print(f'P(C)={Prob_C}') 结果如下:P(C)=0.501162 最后,让我们计算D的概率:N_D_occurs = (one_million_tosses < 5).sum() Prob_D = N_D_occurs/one_million_tosses.shape[0] print(f'P(D)={Prob_D}') ...
print("Original arrays:") print(array_nums) odd_ctr = len(list(filter(lambda x: (x%2 != 0) , array_nums))) even_ctr = len(list(filter(lambda x: (x%2 == 0) , array_nums))) print("\nNumber of even numbers in the above array: ", even_ctr) ...
even_or_odd = lambda a: a%2==0 numbers = [1,2,3,4,5] even = list(map(even_or_odd,numbers)) print(even) # [False, True, False, True, False] 5. 装饰器 装饰器是 Python 的一个特性,它可以在不显式修改现有代码的情况下向现有代码添加一些新功能。
It returnsFalsefor even numbers greater than 2. It checks divisibility only for odd numbers starting from 3 up to the square root of the number. Main Function (print_first_10_primes): Similar to the first method, this function uses a while loop to find and print the first 10 prime numbe...
point1.move(3,4)print(point1.calculate_distance(point2))print(point1.calculate_distance(point1)) 结尾处的print语句给出了以下输出: 5.04.472135954999580.0 这里发生了很多事情。这个类现在有三个方法。move方法接受两个参数x和y,并在self对象上设置值,就像前面示例中的旧reset方法一样。旧的reset方法现在调...