'print str # Prints complete stringprint str[0] # Prints first character of the stringprint str[2:5] # Prints characters starting from 3rd to 5thprint str[2:] # Prints string starting from 3rd characterprint str * 2 # Prints string two timesprint str + "TEST" # Prints concatenated str...
range(0,32)))control_character_re=re.compile('[%s]'%re.escape(control_characters))returncontrol_character_re.sub('',text)input_string=input("请输入一个字符串:")output_string=remove_control_characters(input_string)print("删除控制字符后的字符串为:",output_string)...
)[m|K]'# 使用re.sub函数替换字符串中的终端控制符为空字符串result=re.sub(pattern,'',s)returnresult# 示例:删除字符串中的终端控制符text='\x1b[31mThis is a \x1b[1mtest\x1b[m.'result=remove_control_characters(text)print(result)
print("Character count:", count) root = tk.Tk() text = tk.Text(root) text.bind("<KeyRelease>", count_characters) text.pack() root.mainloop() 10、为Menu组件(菜单)绑定回调函数 import tkinter as tk def say_hello(): print("Hello World!") root = tk.Tk() menubar = tk.Menu(root) ...
importtkinter as tkdefcount_characters(event): text= event.widget.get("1.0","end") count= len(text.replace("\n",""))print("Character count:", count) root=tk.Tk() text=tk.Text(root) text.bind("<KeyRelease>", count_characters) ...
print(“{:*^20}”.format(“hanxiao”))=print(“hanxiao”.center(20,‘*’))#字符串打印的一个技巧<左对齐,^中间对齐,>右对齐"""这种打印的方法等同与使用函数center、ljust,rjust"""print("characters".center(20,'*'))>>>***characters***print("characters".ljust(20,'*'))>>>character**...
#UnicodeEncodeError: ascii codec cant encode characters in position 0-1: ordinal not in range(128)print s print输出异常 有一种情况还是会出现编码异常,就是使用print()时: print(‘测试‘) UnicodeEncodeError: ‘ascii’ codec can’t encode character ‘\uff1a’ in position **: ordinal not in range...
这里最主要的就是\r的理解,通常print语句是会换行的,加上end=""就可以实现不换行了,但是会一直拼接在后面。 为了解决这个问题,就需要理解\r这个内容了。 \n是换行,这个很容易理解,就是另起一行开始。\r是回车,通常我们按下enter键也说回车键,实际中enter键的作用是换行加回车;回车是复位,回到原来的起点位置的...
keyboard.add_hotkey('space',lambda:print('space was pressed!'))# If the program finishes, the hotkey is not in effect anymore.# 如果程序结束了,热键就不再生效了。# Don't do this! This will use 100% of your CPU.# 不要使用下面的代码, 它会占用100%的CPU。#while True: pass# Use th...
>>>word[0:2]# characters from position 0 (included) to 2 (excluded)'Py'>>>word[2:5]# characters from position 2 (included) to 5 (excluded)'tho' 注意切片的开始总是被包括在结果中,而结束不被包括。这使得 s[:i] + s[i:] 总是等于 s ...