If you don’t want to raise an Exception, or you don’t even need to open a file and just need to check if it exists, you have different options. The first way is using the different methods in os.path:os.path.isfile(path): returns True if the path is a valid file os.path....
例如我们可以使用os模块的os.path.exists()方法来检测文件是否存在: importos.path os.path.isfile(fname) 如果你要确定他是文件还是目录,从 Python 3.4 开始可以使用 pathlib 模块提供的面向对象的方法 (Python 2.7 为 pathlib2 模块): frompathlibimportPathmy_file=Path("/path/to/file")ifmy_file.is_file...
Checking if a File Exists This is arguably the easiest way to check if both a file existsandif it is a file. importos os.path.isfile('./file.txt')# Trueos.path.isfile('./link.txt')# Trueos.path.isfile('./fake.txt')# Falseos.path.isfile('./dir')# Falseos.path.isfile('....
1. Python: Check if directory exists using os.path.exists() function os.path.exists()helps check if a specified path exists or not. It returns true if the path is a file, directory, or any other file that contains a reference to another file. It takes a path as an argument and retu...
Check out the following two links: os.path.exists() Return True if path refers to an existing path. os.path.isdir() Return True if path is an existing directory. Share Improve this answer Follow answered Feb 27, 2018 at 4:12 AlanK 9,75388 gold badges4444 silver badges6767 bronze ba...
os.path.exists() 如果目录不存在,会返回一个0值。 所以,如果你如下使用该函数,会得到 Problem 中描述的错误,而且错误会定位在其他地方: importostry: os.path.exists("E:/Contact")#Check if dir existexcept: os.mkdir("E:/Contact")#if not, create ...
1 使用os模块 os模块中的os.path.exists(path)方法用于检验文件/目录是否存在。 ReturnTrueifpathrefers to an existing path or an open file descriptor. ReturnsFalsefor broken symbolic links. 代码语言:javascript 代码运行次数:0 复制 Cloud Studio代码运行 ...
= '{}'.format('dir') for file_tmp in root_elem.findall(mpath, namespaces): file_name = file_tmp.find("file-name", namespaces) elem = file_tmp.find("dir-name", namespaces) if elem is None or file_name is None: continue _, part2 = os.path.splitext(file_name.text) if part2...
= '{}'.format('dir') for file_tmp in root_elem.findall(mpath, namespaces): file_name = file_tmp.find("file-name", namespaces) elem = file_tmp.find("dir-name", namespaces) if elem is None or file_name is None: continue _, part2 = os.path.splitext(file_name.text) if part2...
defcombineVideo(mov,dat_dir=".",fps=24,out_dir="out",out_name=None,skip=0):# out nameifnot os.path.exists(out_dir):os.mkdir(out_dir)ifout_name==None:out_name=mov # 拿到所有分段video的正确顺序的路径 subMovDir=sorted(glob.glob(f"{dat_dir}\\{mov}\\{mov}*"))iflen(subMovDir...