因此所有的方法参数中,有self #文件名 solution.pyclassSolution:defpartition(self, head: Optional[ListNode], x: int) ->Optional[ListNode]:#...if__name__=='__main__':#注意这里的区别...Solution().partition() 如果未来要在其他类里引用该函数,那么import需要写成: #注意这里的区别fromsolutionimportSolutionclasstestPy:deftestMethod(se...
Copyfrom typing import Uniona: Union[int,None] = 123 上面的代码看起来很丑陋，所以 Python 提供了一个 Optional 类型提示：Copyfrom typing import Optionala: Optional[int] = 123 如上例所示， Optional[X] 等同于 Union[X, None] 。此外，如果变量可以是任何类型，我们可以将其标记为 Any 类型：Copyfr...
class Solution: def mergeKLists(self, lists: List[Optional[ListNode]]) -> Optional[ListNode]: if not lists: return None return self.mergeKList(lists, 0, len(lists) - 1) def mergeKList(self,lists: List[Optional[ListNode]], start: int, end: int) -> Optional[ListNode]: if start == ...
self.val=val self.next=nextclassSolution:defpartition(self, head: Optional[ListNode], x: int) ->Optional[ListNode]: lessListPre= ListNode()#小于链表的伪头节点noLessListPre = ListNode()#不小于链表的伪头节点lessNode = lessListPre#小于链表当前最后一个节点,初始为伪头节点noLessNode = noLessList...
# class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def deleteMiddle(self, head: Optional[ListNode]) -> Optional[ListNode]: if head.next == None: return fast = head ...
class Solution: def mergeTwoLists(self, list1: Optional[ListNode], list2: Optional[ListNode]) -> Optional[ListNode]: prehead = ListNode(-1) # 创建一个虚拟头节点 pre = prehead while list1 and list2: if list1.val < list2.val: pre.next = list1 list1 = list1.next else: ...
class Solution: def reverseList(self, head: Optional[ListNode]) -> Optional[ListNode]: cur,pre = head,None while cur : temp,cur.next,pre,cur = cur.next,pre,cur,temp return pre 运行直接报错了,我也感觉不对劲。后来想到python的多重赋值的一个常见用法a,b = b,a,反应过来了,python的多重...
class Solution: def addTwoNumbers(self, l1: Optional[ListNode], l2: Optional[ListNode]) -> Optional[ListNode]: add1=0 sum = ListNode(0) current = sum while(l1 or l2 or add1): x = l1.val if l1 else 0 ''' 这个表示下面的缩写 if l1: l1 = l1.next else: l1 = None ''' y ...
cur.next = ListNode(next1) return result.next 1. 2. 3. python 代码 class Solution: def addTwoNumbers(self, l1: Optional[ListNode], l2: Optional[ListNode]) -> Optional[ListNode]: total = 0 next1 = 0 result = ListNode() cur = result ...
14 ListNode start = dummy, end = dummy; 15 //让start先向前移动n个 16 while(n != 0){ 17 start = start.next; 18 n--; 19 } 20 //start和end都向前移动 21 while(start.next != null){ 22 start = start.next; 23 end = end.next; ...