可以使用循环结构和条件语句来计算 [1 - n] 之间的奇数和与偶数和，具体代码如下：def sum_of_odd_and_even(n):odd_sum = 0 even_sum = 0 for i in range(1, n+1):if i % 2 == 0:even_sum += i else:odd_sum += i return odd_sum, even_sum# 计算 1~10 之间的奇...
请用程序实现: 输入一个整数,判断它是奇数还是偶数。如果是奇数,输出odd;如果是偶数,输出even。 num=int(input("请输入一个数")) # 请判断这个数是奇数还是偶数 if (num%2==0): print("even") else: print("odd") 1. 2. 3. 4. 5. 6. 7. 2.公倍数 请用程序实现输入一个正整数,判断它是否...
Logic to Find Odd and Even NumbersTo find odd and even numbers from the list of integers, we will simply go through the list and check whether the number is divisible by 2 or not, if it is divisible by 2, then the number is EVEN otherwise it is ODD.Python...
odd, even = [el for el in a if el % 2==1], [el for el in a if el % 2==0]print(odd,even)> ([1, 3, 5, 7, 9], [2, 4, 6, 8, 10]) 俊红的数据分析之路 《对比Excel》系列图书作者,出版有Python数据分析、SQL数据分析、P...
print("{} is EVEN.".format(x)) else: print("{} is ODD.".format(x)) 10. 输入两个自然数a和b,判断b是否是a的因数,输出判断结果。 a,b=eval(input()) if a%b==0: print("{} is a factor of {}.".format(b,a)) else:
numbers = [12, 37, 5, 42, 8, 3] even = [] odd = [] while len(numbers) > 0: number = numbers.pop() if(number % 2 == 0): #偶数判断 even.append(number) else: odd.append(number) #输出结果 print(even) print(odd) 输出结果如下: [8, 42, 12] [3, 5, 37] 2.for循环 ...
even.append(i) returnodd,even #函数的调用 lst=[10,29,34,23,44,53,55] print(fun(lst)) 执行结果: 说明: 函数的返回值: (1)如果函数没有返回值【函数执行完毕之后,不需要给调用处提供数据】return可以省略不写 (2)函数的返回值,如果是1个,直接返回原类型 ...
Write a Python program to determine if a given number is odd and a multiple of 7. Write a script that categorizes a number as "Even and Positive," "Odd and Positive," "Even and Negative," or "Odd and Negative." Write a program that accepts a number and prints all even or odd num...
Python3 实例 以下实例用于判断一个数字是否为奇数或偶数: 实例(Python 3.0+) # Filename : test.py# author by : www.runoob.com# Python 判断奇数偶数# 如果是偶数除于 2 余数为 0# 如果余数为 1 则为奇数num=int(input("输入一个数字:"))if(num%2)==0:print("{0} 是偶数".format(num))else...
代码示例如下：num = input("Enter a number, and I'll tell you if it's even or odd:")num = int(num)if num % 2 == 0: print("The number " + str(num) + " is even.")else: print("The number " + str(num) + " is odd.")第二种方法：函数divmod() 取余数 1 ...