text="""This is a long multiline string."""text=text.replace('\n',' ')print(text) 1. 2. 3. 4. 5. 6. 在上述代码中,我们首先定义了一个多行字符串text,其中包含了三行文本。然后,我们使用replace()方法将每个换行符替换为一个空格。最后,我们打印出结果: This is a long m
importtextwrap string1='''Hello This is a multiline string With multiple lines'''string2='''World In Python Concatenation'''wrapped_lines1=textwrap.wrap(string1)wrapped_lines2=textwrap.wrap(string2)max_lines=max(len(wrapped_lines1),len(wrapped_lines2))horizontal_concatenation='\n'.join(wrapp...
In this approach, you can first store the multiline string in a list or tuple, as a list of lines. Then you can join all the lines with the newline character and the join() string method. For example: >>>x=('abcd',...'efghi',...'jklmn')>>>print('\n'.join(x))abcd efg...
Using implicit line continuation and string concatenation does work. But there's a better way to represent strings that span over multiple lines of text in Python.Multiline stringsThis is a multiline string:usage = """Welcome to stopwatch! This script counts slowly upward, one second per ...
print(re.findall("^This.*", mystring, re.MULTILINE)) ['This is some random text.', 'This is Goodbye.'] Here we have both lines which started with “This” printed out. This is because the pattern was applied to all three lines, from which the first and third line matched. ...
multiline_text = """This is a multiline string. It can span multiple lines. # ...Use \n to insert a line break.""" print(multiline_text)输出结果：This is a multiline string. It can span multiple lines. Use \n to insert a line break.在这个例子中，"\n"用于在多行字符...
Guido van Rossum '''This is a multi-line string. ''' 浏览5提问于2021-03-06得票数0 回答已采纳 1回答 Python多行注释 、 我正在努力处理Python语言中的多行注释,我知道我可以在每行多行注释的开头使用#,但在注释的开始和结尾也有另一种使用"""的方法;然而,在我的解释器中,"""方法给出了一个输出...
name = "Alice" greeting = 'Hello, world!' multiline_text = """This is a multiline string.""" 1.4 布尔值(bool) 布尔值只有两个值:True 和False。它们通常用于条件判断。 示例: is_active = True is_closed = False 1.5 基本数据类型示意图 +---+ +---+ | int | ---> | 10 | +-...
sentences = re.findall(r'^[A-Z].*$', text, re.MULTILINE) print("以大写字母开头的句子:...
MULTILINE) text = '123\n456\n789' result = pattern.findall(text) print(result) # 输出: ['123', '456', '789'] re.DOTALL 或 re.S: 使. 匹配包括换行符在内的任意字符。 import re pattern = re.compile(r'a.b', flags=re.DOTALL) result = pattern.match('a\nb') print(result....