if alist[location] > alist[positionOfMax]: #将最大项的下标替换为当前项 positionOfMax = location #当遍历结束后,将最大项放到剩余list的最后一项(交换剩余项的最后一项与最大项) alist[fillslot], alist[positionOfMax] = alist[positionOfMax], alist[fillslot
def find_min(alist): #假设alist中的第一个数字最小 my_min = alist[0] #遍历alist for i in alist: #最小标记flag指示i是否为alist最小,初始为True flag = True #遍历alist for j in alist: #如果i>j(存在比i小的数) if i >j: #标记flag为false flag = False #当i为alist最小,my_...
def shell_sort(a_list): sublist_count = len(a_list) // 2 while sublist_count > 0: for pos_start in range(sublist_count): gap_insertion_sort(a_list, pos_start, sublist_count) print("After increments of size", sublist_count, "the list is", a_list) sublist_count = sublist_count...
A simple equation that contains one variable likex−4−2=0x−4−2=0can be solved using the SymPy'ssolve()function. When only one value is part of the solution, the solution is in the form of a list. The code section below demonstrates SymPy'ssolve()function when an expression ...
Problem Solving with Algorithms and Data Structures using python 热度: Data Structures and Problem Solving Using C 2nd Instructors Resource Manual 热度: Data Structures and Algorithms Using Python 热度: 目录 致谢 Introduction 1.介绍 1.1.目标
迷宫生成算法在游戏开发和图形学中有着广泛的应用。它不仅可以用于创建迷宫游戏，还可以用于生成有趣的...
When we reach the point where the problem is as simple as it can get, we begin to piece together the solutions of each of the small problems until the initial problem is solved. Figure 4.2 shows the additions that are performed as list_sum works its way backward through the ...
1.# Good 3.my_list = [1, 2, 3, 4, 5] 5.my_dict = {'key1': 'value1', 'key2': 'value2'} 7.my_name = "Frank" 我还把我的变量 x的名字改为 my_name。这不是Pycharm建议的,但PEP8建议使用容易理解的变量名。 6. 在处理字典时没有正确使用.key和.values方法 ...
merge_sort(right_half)# 当左右两个sublist都排好序时,每次选择两个sublist的最小的数# 然后在这两数中选择更小的数依次放入待返回的list中i,j,k=0,0,0whilei<len(left_half)andj<len(right_half):ifleft_half[i] < right_half[j]: a_list[k] = left_half[i] ...
When we simply use the copy assignment we only copy the reference to the List: a=[1,2,3]b=a Both objects point to the same memory location, so changing one List also affects the other one! b.append(4)print(b)# [1, 2, 3, 4]print(a)# [1, 2, 3, 4] ...