使用str.join()方法将列表转换为逗号分隔的字符串,例如my_str = ','.join(my_list)。str.join() # ✅ Convert list of strings to comma-separated string # ✅ 将字符串列表转换为逗号分隔的字符串 list_of_strings = ['one', 'two', 'three'] my_str = ','.join(list_of_strings) print(m...
2.1 string → list 常见的字符串 → 列表 >>> string = 'x1y2' >>> list(string) ## 1.强制类型转换 ['x', '1', 'y', '2'] >>> [str(char) for char in string] ## 2.列表解析式 A ['x', '1', 'y', '2'] >>> list(map(lambda z:str(z),'x1y2')) ## 2.列表解析...
同find,不过是从字符串右到左,不过返回的是子字符串最左边的第一个字符位置16、S.split(sep=None, maxsplit=-1) ->list of strings 返回一个以sep作为分隔符得到的列表。maxsplit代表分隔几次,默认为全分隔17、S.rsplit(sep=None, maxsplit=-1) ->list of strings 同上。不过是从右至左18、S.splitline...
is a separator."""return[]defsplit(self, sep=None, maxsplit=-1):#real signature unknown; restored from __doc__"""S.split(sep=None, maxsplit=-1) -> list of strings Return a list of the words in S, using sep as the delimiter string. If maxsplit is given, at most maxsplit spl...
可以先统计列表中每一个元素的数目，然后用表理解选择出统计数目大于的的元素 myList = ["StarWars","cs116","StarWars"]count = {}for item in myList: count[item] = count.get(item, 0) + 1 result = [k for k,v in count.items() if v>=2]print result ...
S.split(sep=None, maxsplit=-1) -> list of strings Return a list of the words in S, using sep as the delimiter string. If maxsplit is given, at most maxsplit splits are done. If sep is not specified or is None, any whitespace string is a separator and empty strings are ...
将可迭代对象(iterable)中的字符串使用string连接起来。注意,iterable中必须全部是字符串类型,否则报错。如果你还是python的初学者,还不知道iterable是什么,却想来看看join的具体语法,那么你可以暂时将它理解为:字符串string、列表list、元组tuple、字典dict、集合set。当然还有生成器generator等也可以用该方法。
res = json.loads(stringA)# Result print("The converted list : \n",res)输出 The converted list :['geeks', 2, 'for', 4, 'geeks', 3]7. 使用ast.literal 在Python中，有个ast模块，它有一个litera_eval方法，我们也可以通过它来进行转换。import ast # initializing string representation of a ...
print(list(map(funtor,li))) 执行结果: /home/kiosk/PycharmProjects/westos5/venv/bin/python /home/kiosk/PycharmProjects/westos5/内置地高阶函数.py [3, 7, 3, 3, 2, 5, 3, 2, 2, 4] [6, 5040, 6, 6, 2, 120, 6, 2, 2, 24] ...