Our 3-part series about linked lists in Python: Part 1 - "Linked Lists in Detail with Python Examples: Single Linked Lists" Part 2 - "Sorting and Merging Single Linked List" Part 3 - "Doubly Linked List with Python Examples" Single Linked List A single linked list is the simplest of ...
listone = [2, 3, 4] listtwo = [2*i for i in listone if i > 2] print(listtwo) 1. 2. 3. ###在函数中接收元组与字典 可以分别使用 * 或 ** 作为元组或字典的前缀,来使它们作为一个参数为函数所接收。示例: def powersum(power, *args): '''Return the sum of each argument raised t...
b = list(range(10)) # [0, 1, 2, 3, 4, 5, 6, 7, 8, 9],包前不包后 c = list(range(3,20,2)) # [3, 5, 7, 9, 11, 13, 15, 17, 19] d = list(range(20,3,-2)) # [20, 18, 16, 14, 12, 10, 8, 6, 4],步长为负数时递减 e = list(range(3,-10,-1)) ...
for item in my_list: if item == 2: count += 1 # 输出结果 print(count) 在这个例子中,输出结果同样为4,表示元素2在List中出现了4次。虽然这种方法代码较长,但它提供了更大的灵活性,适用于更复杂的统计需求。 需要注意的是,以上两种方法都是就地操作,不会改变原始List中的元素顺序。如果你需要同时得到...
方法一:使用内置函数list()这是最简单的方法,只需将Set对象作为参数传递给list()函数即可。例如: my_set = {1, 2, 3, 4, 5} my_list = list(my_set) print(my_list) 方法二:使用for循环遍历Set对象另一种常见的方法是使用for循环遍历Set对象,并将每个元素添加到一个新的List对象中。例如: my_set ...
def pingjun(L=[]): a=reduce(lambda x,y:x+y,L) return a*1.0/len(L) L=[] for i in range(0,10): num=input('enter your score:') L.append(int(num)) L.remove(max(L)) L.remove(min(L)) print(pingjun(L)) 这个函数并不能去掉最大值,而且求平均值的函数会报错,求解...
编写一个Python函数,接收一个整数列表作为参数,返回列表中所有偶数的平均值。```pythondef average_even(numbers):evens = [x for x in numbers if x % 2 == 0]if len(evens) == 0:return 0return sum(evens) / len(evens)numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]print(a
利用list() L3 = list(L0) L3[0] = 100 print(L0) 利用列表方法extend L4 = [] L4.extend(L0) L4[0] = 100 print(L0) 利用列表推导 L5 = [i for i in L0] L5[0] = 100 print(L0) 可以看到最终的打印结果都是[1, 2, 3, 4, 5],我们成功进行了列表的复制,但是为了条件需要是列表...
('.zsxx_cont_list a') for node in node_list: detail_info_url = node['href'] if detail_info_url[:2] == '..': detail_info_url = self.domain + detail_info_url.replace('../../', "") detail_title = node.select('p')[0].text.split()[0] detail_date = node.select('span...
for li in li_list: detail_url ='https://pic.netbian.com' + li.xpath('./img/@src')[0] detail_name = li.xpath('./img/@alt')[0]+'.jpg' detail_name = detail_name.encode('iso-8859-1').decode('GBK') detail_path = './piclibs/' + detail_name ...