for i in arg: if isinstance(i, list): ret.extend(i) else: ret.append(i) return ret def deep_flatten(lst): result = [] result.extend( spread(list(map(lambda x: deep_flatten(x) if type(x) == list else x, lst))) return result deep_flatten([1, [2], [[3], 4], 5]) #...
def find_duplicates(lst): duplicates = [] seen = set() for item in lst: if item in seen: duplicates.append(item) else: seen.add(item) return duplicates # 示例用法 my_lst = [1, 2, 3, 4, 3, 2, 1, 5] result = find_duplicates(my_lst) print(result) # 输出 [1, 2, 3] 复...
我们可以利用Counter类来判断一个列表中是否有重复的元素。 fromcollectionsimportCounterdefcheck_duplicates(lst):counter=Counter(lst)returnany(count>1forcountincounter.values())data=[1,2,3,4,5,1]ifcheck_duplicates(data):print("List contains duplicates")else:print("List does not contain duplicates")...
# print the duplicated values. idx.get_duplicates() 输出: 正如我们在输出中看到的,Index.get_duplicates()函数返回了在索引中出现多次的所有值。示例 #2:使用Index.get_duplicates()函数查找索引中的所有重复项。该索引还包含NaN值。 # importing pandas as pd import pandas as pd # Creating the Index idx...
# Python 3.7及以上版本可以保持相对顺序 unique_list_sorted = sorted(set(original_list)) # 若要...
returnlist(set(input_list))duplicates=[1,2,2,3,4,4,5,6,6]result=remove_duplicates(duplicates...
To get all duplicates, you can use the below method, but it is not very efficient. If efficiency is important you should consider Ignacio's solution instead. >>> dict((x, indices(List, x)) for x in set(List) if List.count(x) > 1) ...
('isList', '0'), ) response = requests.get('https://search.xxxx.com/s_new.php', headers=headers, params=params, proxies=proxies) response_beau = BeautifulSoup(response.text, 'lxml') return response_beau 通过这个请求,可以获取到的商品信息如下 ...
Allow Duplicates Since lists are indexed, lists can have items with the same value: Example Lists allow duplicate values: thislist = ["apple","banana","cherry","apple","cherry"] print(thislist) Try it Yourself » To determine how many items a list has, use thelen()function: ...
numbers=[1,2,3,4,5,1]# 假设存在重复元素的列表ifhas_duplicates(numbers):# 调用has_duplicates函数判断列表是否存在重复元素print("列表中存在重复元素")else:print("列表中不存在重复元素") 1. 2. 3. 4. 5. 在以上示例中,我们创建了一个名为numbers的列表,其中包含了重复的元素1。然后我们调用has_dup...