:type index: int :rtype: int """ if 0<=index<self._count: p=self._head for _ in range(index+1):p=p.next return p.val else:return -1 def addAtHead(self, val):#头部添加节点 """ :type val: int :rtype: None """ self.addAtIndex(0, val) def addAtTail(self, val): #...
List- elements: Element[]+addElement(element: Element) : void+removeElement(element: Element) : voidElement- value: any+getValue() : any+setValue(value: any) : voidIndex- value: int+getValue() : int+setValue(value: int) : void 上述类图展示了列表、元素和索引之间的类关系。列表类拥有一...
Python表达式结果描述len([1, 2, 3])3list的长度[1, 2, 3] + [4, 5, 6][1, 2, 3, 4, 5, 6]组合[‘Hi~’] * 4[‘Hi~’, ‘Hi~’, ‘Hi~’, ‘Hi~’]重复3 in [1, 2, 3]True元素是否存在于list中for x in [1, 2, 3]: print(x, end=” “)1 2 3遍历list中的元素 2...
修复IndexError: list assignment index out of range 使用 append() 函数 append() 函数在列表末尾添加项目(值、字符串、对象等)。 这很有帮助,因为您不必处理索引问题。 代码示例: a = [1,2,3,4,5,6] b = [] k = 0 for l in a: # use append to add values at the end of the list j....
value is not found in the sequence, the function raises a ValueError. For example, if we have a list[1, 2, 3, 4, 5], we can find the index of the value3by callinglist.index(3), which will return the value2(since3is the third element in the list, and indexing starts at 0)....
4、index index方法用于从列表中找出某个值第一个匹配项的索引位置: 举例: >>> s='He who commences many things finishes but a few'>>> list1=s.split()>>>list1 ['He','who','commences','many','things','finishes','but','a','few']>>> list1.index('who')1 ...
|insert(...)| L.insert(index, object) --insert object before index| |pop(...)| L.pop([index]) -> item -- removeandreturnitem at index (default last).| Raises IndexErroriflistisemptyorindexisout of range.| |remove(...)| L.remove(value) -> None --remove first occurrence of ...
| list(iterable) -> new list initialized from iterable's items | | Methods defined here:各种方法的使用 | 1.__add__(...)列表相加,相当于连接 | x.__add__(y) <==> x+y | 例:方法1: 方法2:(两种方法结果一样,对于后面的介绍,只对一种举例介绍 ...
Here, we are going to learn how to create a list from the specified start to end index of another (given) list in Python.
print(fruits[0]) #index 0 is the first element print(fruits[1])print(fruits[2])Output:Apple Banana Orange 但是，索引不必总是为正。如果想逆向访问列表，也就是按照相反的顺序，可以使用负索引，如下所示：#Access elements in the fruits list using negative indexesfruits = ['Apple','Banana', "...