有时可能会遇到以下错误信息："TypeError: a bytes-like object is required, not 'str'"。
复制 >>> odd = lambda x : bool(x %2)>>> numbers = [nforn in range(10)]>>>fori in range(len(numbers)):...ifodd(numbers[i]):... del numbers[i] # 在列表上进行迭代时删除列表中的项目...Traceback (most recent call last): File"<stdin>", line2, in <module>IndexError: lis...
Python中str is not callable问题详解及解决办法 问题提出：在Python的代码，在运⾏过程中，碰到了⼀个错误信息：python代码：def check_province_code(province, country):num = len(province)while num <3:province = ''.join([str(0),province])num = num +1 return country + province 运⾏的错误...
用函数名声明变量 在以下示例中,我们声明一个名为len的变量。在某些时候,当我们调用len()函数来检查输入时,我们会收到错误: len = '' # len is set to an empty string name = input('Input your name: ') # Raises TypeError: 'str' object is not callable if (len(name)): print(f'Welcome, {...
len(my_tuple):返回元组的长度 max(my_tuple):返回元组中的最大值 min(my_tuple):返回元组中的最小值 sum(my_tuple):返回元组中所有元素的和 6、元组与列表的转换 可以使用list()和tuple()函数将元组和列表相互转换。 将元组转换为列表:my_list = list(my_tuple) ...
def validate_responses(responses): for response in responses: # Make sure that `id` exists if 'id' not in response: return False # Make sure it is a string if not isinstance(response['id'], str): return False # Make sure it is 20 characters if len(response['id']) != 20: return...
s = random.sample(a, min(len(a), 2)) print(s) 28. 格式化输出错误 (TypeError: not enough arguments for format string) a = 10 b = 20 print("a = %d, b = %d" % a, b) # 这里需要一个元组. 上面的第三句本意是格式化输出两个变量的值,百分号后面需要一个元组。修改如下, ...
将range(t)改为range(len(t)) 4.2入参个数错误 4.2.1关于元组作为入参 代码: # coding=utf-8 ''' Created on 2016-7-21 @author: Jennifer Project:显式等待 ''' from selenium import webdriver fromselenium.webdriver.common.byimport By
python报错'str' object is not callable >>> x=1.235 >>> int(x) 1 >>> str="fsgavfdbafdbntsbgbt" >>> len(str) 19 >>> >>> x=987456123 >>> str(x) 会报错'str' object is not callable。 str()是系统自带的,你不能在用它的时候自己同时定义一个别的叫做str的变量,这样会冲突。
s = 'CCACCCTCGTGGTATGGCTAGGCATTCAGGAACCGGAGAACGCTTCAGACCAGCCCGGACTGGGAACCTGCGGGCAGTAGGTGGAAT'print len(s)count_C = 0count_G = 0for char in s: #print char if char == 'C': count_C += 1 if char == 'G': count_G = count_G + 1print 'C count: '...