程序用户程序用户输入年份调用is_leap_year函数判断是否满足闰年条件返回结果 类图 下面是一个简单的类图,展示了闰年判断函数所在的类: LeapYearFunction+is_leap_year(year:int) : bool 在上面的类图中,LeapYearFunction类包含一个is_leap_year方法,该方法接受一个整型参数年份,并返回一个布尔值表示该年份是否为闰年。
def function1(i, j, k): # 计算给定日期是那一年的第几天 leap_year = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] no_leap_year = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] if isLeapYear(i): result = sum(leap_year[:j - 1]) + k else: resul...
1、定义一个is_leap(year)函数,该函数可以判度year是否为闰年。若是闰年,则返回True;否则返回False。 import sys def is_leap(year): year = int(year) if year % 4 != 0: return False elif year % 100 != 0: return True elif year % 400 != 0: return False else: return True while(True)...
6.程序实现的功能:输人某年某月某日,判断这一天是这一年的第几天,Python代码如下: d e f leap(year):$$ l e a p = 0 $$$ i f ( y e a r \% 4 0 0 = = 0 ) o r ( ( y e a r \% 4 = = 0 ) a n d ( y e a r \% 1 0 0 ! = 0 ) ) : $$$ l e a ...
Python程序LeapYear源码 import math def valid(month,day,year):if day>31:return False elif month==2:if leap(year):if day <=29:return True else:return False else:if day<=28:return True else:return False elif month==4 or 6 or 9 or 11:if day>31:return False else:return True else:r...
If the year is not divisible by 400, it means it’s not a leap year. If the year is not divisible by 100 (as per the second condition), it directly returns True, indicating a leap year. If the year is not divisible by 4 in the first check, the function returns False, which mean...
defisLeapYear(y):# 判断闰年的函数if(y%4==0andy%100!=0)ory%400==0:# 是闰年 返回TruereturnTrueelse:returnFalse# 否则返回Falsedeffunction1(i,j,k):# 计算给定日期是那一年的第几天leap_year=[31,29,31,30,31,30,31,31,30,31,30,31]no_leap_year=[31,28,31,30,31,30,31,31,30,31...
Python的函数也是一种值。所有函数都是 function 对象,可以把函数本身赋值给变量,就像把整数、列表、元组等赋值给变量一样。把函数赋值给变量后,就可通过变量来调用函数。示例如下: 1defpow(base, exponent):2"""计算乘方"""3result = 14foriinrange(1, exponent + 1):5result *=base6returnresult7my_fun...
Write a Python program to determine if a given year is a leap year using boolean expressions and output an appropriate message. Write a Python function to check leap year status based on divisibility rules (divisible by 4, not 100, unless divisible by 400) and return a boolean result. ...
1 TypeError: is_leap_year() takes 0 positional arguments but 1 was given 问题分析: 报错的意思是:is_leap_year()这个函数不需要参数,但是函数却被传递了一个参数。 掉头检查代码,会发现: 1 def is_leap_year(): 这里出了问题,我们对其进行修改: 1 def is_leap_year(year): 再次运行代码,成功...