LeetCode(https://leetcode.com/)LeetCode 是一个非常受欢迎的在线编程练习平台，提供了大量关于数据结...
*/ for (int i = 2; i <= upper_border; i++) { num[i] = 1; } /* * This is a normal option to judge * if a dividend is a prime number. */ for (int dividend = 2; dividend <= upper_border; dividend++) { for (int divisor = 2; divisor * divisor <= dividend; divisor...
for (int i = 0; i < Number; i++) { if (match[i] == 0) break; printf(" Is '%s' the book you would find?(Y/N)\n\n", Books[i]); char Judge; scanf("%s", &Judge); getchar(); if (Judge == 'Y' || Judge == 'y') { flag = 1; printf(" Congratulations! You fi...
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if not (self.judge is None): this_string = this_string + 'label : ' + self.judge return this_string 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. 26.
n =int(input())# 输入ID,整数,保证是两个素数的积number =int(input())# 输入0-9之间的一个数字ID = checkId(n) countNumber = countnumber(ID,number)# 统计 number的个数print('WHUT'+str(ID))print(countNumber)# def occ3(n,num):# s = 0# for i in range(len(str(n))):# x = ...
import redef judge_phone_number(account):pattern = re.compile(r"^1([3-9])\d{9}$")if pattern.match(account):print("手机号码输入正确")else:print("手机号码输入错误")judge_phone_number(input("请输入手机号:")) 注: Python个中的正则表达式放在单、双引号里面,前面加一个r表示原始字符串,不进行...
# judge_new_user.py import os def is_new_user(user_name: str, folder_path: str): """ 判断一个用户是否已经存在。 Args: user_name (str): 用户名 folder_path (): 文件夹路径 Returns: """ file_path = os.path.join(folder_path, user_name + ".txt") if not os.path.exists(file_...
如果传入的文本型数字是其他进制的,需为进制参数base赋值(base的可填参数:0,2至36,默认是10)3、int()返回0| Convert a number or string to an integer, or return 0 if no arguments| are given. If x is a number, return x.__int__(). For floating point| numbers, this truncates towards ...
#include int judge(int x,int y,int z){int m; if (((x+y)》z)&&((x-y)y)&&((x-z)x)&&((y-z)main(){int a,b,c,n;printf(“请输入a,b,c“);scanf(“%d%d%d“,&a,&b,&c);n=judge(a,b,c);if (n==1)if (((a*a+b*b)==c*c)||((a*a+c*c)==b*b)||(b*b...