Return the intersection of two sets as a new set 求2个集合的交集(也就是取出来既会py又会linux的人) python_1 = ["ggq","ytj","mr","mr","ggq"] linux_1= ["ggq","ytj"] p_s= set(python_1)#把列表转换为集合l_s = set(linux_1)#把列表转换为集合print(p_s,l_s)print(p_s.int...
| intersection(...) | Return the intersection of two or more sets as a new set. | | (i.e. elements that are common to all of the sets.) | | intersection_update(...) | Update a set with the intersection of itself and another. | | isdisjoint(...) | Return True if two sets ...
移除指定元素,不存在不保错 """ pass def intersection(self, *args, **kwargs): # real signature unknown """ Return the intersection of two sets as a new set. 交集 (i.e. all elements that are in both sets.) """ pass def intersection_update(self, *args, **kwargs): # real signatu...
| Return the difference of two or more sets as a new set. | | (i.e. all elements that are in this set but not the others.) | | intersection(...) | Return the intersection of two sets as a new set. | | (i.e. all elements that are in both sets.) | | isdisjoint(...)...
def intersection(self, *args, **kwargs): # real signature unknown """ Return the intersection of two sets as a new set. 交集 (i.e. all elements that are in both sets.) """ pass def intersection_update(self, *args, **kwargs): # real signature unknown ...
很多新手忽视sets(集合)和tuple(元组)的强大之处 例如,取两个列表交集: def common_elements(list1, list2): common = [] for item1 in list1: if item1 in list2: common.append( item1 ) 、 return common 这样写会更好: def common_elements(list1, list2): common = set(list1).intersection(...
Return the intersection of two sets as a new set. 交集 (i.e. all elements that are in both sets.) """ pass def intersection_update(self, *args, **kwargs): # real signature unknown """ Update a set with the intersection of itself and another. 取交集并更更新到A中 """ ...
Return the intersection of two sets as a new set. (i.e. all elements that are in both sets.)"""passdefintersection_update(self, *args, **kwargs):#real signature unknown"""Update a set with the intersection of itself and another."""passdefisdisjoint(self, *args, **kwargs):#real ...
intersection() & Returns a set, that is the intersection of two other sets intersection_update() &= Removes the items in this set that are not present in other, specified set(s) isdisjoint() Returns whether two sets have a intersection or not issubset() <= Returns whether another set con...
intersection()、intersection_update()求交集 intersection(…) Returnthe intersectionoftwoormore setsasa newset. 返回一个由若干个集合经过交集运算后得到的新交集,可以传入多个迭代器类型的参数。即可以传递Tuple、List、、String、Dictionary、Set等类型参数。