#Intersection of two list (Get the elements that both have) list(set(list1) & set(list2)) 获得后者相对于前者的补集 #Difference of two list (Get the elements that the former have, the latter don't) list(set(list1) - set(list2)) 获得两个list的差集 #Symmetric difference of two list...
x, y=pointifline0_x2y2[0] == line0_x1y1[0]:#垂直线returnx == line0_x1y1[0]andline0_x1y1[1] <= y <= line0_x2y2[1]elifline0_x2y2[1] == line0_x1y1[1]:#水平线returny == line0_x2y2[1]andline0_x1y1[0] <= x <=line0_x2y2[0]else:#斜线return(x - line...
In[9]:tup=tuple(['foo',[1,2],True])In[10]:tup[2]=False---TypeErrorTraceback(most recent call last)<ipython-input-10-c7308343b841>in<module>()--->1tup[2]=FalseTypeError:'tuple'object does not support item assignment 如果元组中的某个对象是可变的,比如列表,可以在原位进行修改: 可以...
LineString from shapely.geometry.polygon import Polygon def get_cross_point_linesegment(line1, line2): """ 求两条线段的交点, 兼容水平线和垂直线 :param line1: ((x1,y1),(x2,y2)) :param line2: ((x1,y1),(x2,y2)) """ # x = (b0*c1 – b1*c0)/D # ...
( line1, line2 ) tries to deal with the fact that line1 and line2 define line segments, and there may be no point of intersection between them even when they aren't parallel (i.e., when the intersection point between the infinite lines isn't part of (at least one of) the finite...
入门知识拾遗 一、python缓冲池简介 python中有缓冲池的概念,实际上就是python解释器启动时开辟的一块内存空间,作用如下: 1. 提高代码的执行效率 2. 减轻内存的负担 比如会将经常用到的数字和字母,放入缓冲池中,重复使用的时候去缓冲池里面去取出来,不用重复申请内存
In [81]: seq[::2] Out[81]: [7, 3, 3, 6, 1] 一个聪明的方法是使用-1,它可以将列表或元组颠倒过来: In [82]: seq[::-1] Out[82]: [1, 0, 6, 5, 3, 6, 3, 2, 7] 序列函数 Python有一些有用的序列函数。 enumerate函数 迭代一个序列时,你可能想跟踪当前项的序号。手动的方法可...
intersection, result_sets) result = sorted(result) # must sort to support start, stop result_iter = itertools.islice(result, start, stop) return QueryResult(len(result), (char for char in result_iter)) def describe(self, char): code_str = 'U+{:04X}'.format(ord(char)) name = ...
tup # 输出:('foo', [1, 2, 3], True) 可以⽤加号运算符将元组串联起来: (4, None, 'foo') + (6, 0) + ('bar',) # 结果如下:(4, None, 'foo', 6, 0, 'bar') 元组乘以⼀个整数,像列表⼀样,会将⼏个元组的复制串联起来: ...
, :2] ls = sgeom.LineString(xyt.tolist()) locs = axis.intersection(ls) if not locs: tick = [None] else: tick = tick_extractor(locs.xy) _ticks.append(tick[0]) # Remove ticks that aren't visible: ticklabels = copy(ticks) while True: try: index = _ticks.index(None) except ...