python inspect.stack() 的简单使用 1. #python#-*- encoding: utf-8 -*-#获取函数的名字importinspectdefdebug(): callnamer=inspect.stack()print('[debug] enter: {}'.format(callnamer)) debug() [debug] enter: [FrameInfo(frame=<
python inspect.stack() 的简单使用 1. #python#-*- encoding: utf-8 -*-#获取函数的名字importinspectdefdebug(): callnamer=inspect.stack()print('[debug] enter: {}'.format(callnamer)) debug() [debug] enter: [FrameInfo(frame=, filename='E:/pythontest/sort.py', lineno=6, function='debu...
lineno=6, function='debug', code_context=[' callnamer = inspect.stack()\n'], index=0), FrameInfo(frame=, filename='E:/pythontest/sort.py', lineno=9, function='<module>', code_context=['debug()\n'], index=0)] 1. 可以看出是一个列表 2.选取列表的...
inspect.isroutine(object)¶ Return True if the object is a user-defined or built-in function or method. inspect.isabstract(object)¶ Return True if the object is an abstract base class. inspect.ismethoddescriptor(object)¶ Return True if the object is a method descriptor, but not if ...
1. inspect.getmembers(object[, predicate]) 第二个参数通常可以根据需要调用如下16个方法; 返回值为object的所有成员,以(name,value)对组成的列表 inspect.ismodule(object): 是否为模块 inspect.isclass(object):是否为类 inspect.ismethod(object):是否为方法(bound method written in python) inspect.isfu...
pythoninspect.stack（）的简单使⽤ 1.#python # -*- encoding: utf-8 -*- #获取函数的名字 import inspect def debug():callnamer = inspect.stack()print('[debug] enter: {}'.format(callnamer))debug()[debug] enter: [FrameInfo(frame=, filename='E:/pythontest/sort.py', lineno=6, functi...
inspect.stack(context=1) Return a list of frame records for the caller's stack. The first entry in the returned list represents the caller; the last entry represents the outermost call on the stack. 在3.5 版更改: A list of named tuples FrameInfo(frame, filename, lineno, function, code...
caller_name=inspect.stack()[1][3]print'[BEBUG]: enter {}()'.format(caller_name)deffunc_enter():debug()print"enter!"deffunc_quit():debug()print"enter!"# bug hereif__name__=='__main__':func_enter()func_quit() 看起来会好一点, 但是每个函数都要调用一次debug()函数,还是不太够, ...
When an error occurs, you can inspect the current program state, including the call stack. However, if you step through the code, the debugging process continues to throw the exception until it's handled or your program exits.To see an expanded view of exceptions, select Debug > Windows >...
import inspect caller_name = inspect.stack()[1][3] print "[DEBUG]: enter {}()".format(caller_name) def say_hello(): debug() print "hello!"def say_goodbye(): debug() print "goodbye!"if __name__ == '__main__': say_hello() ...