//Insert A[j] into the sorted sequence A[1... j-1] i = j - 1 while i > 0 and A[i] > key A[i+1] = A[i] i =i - 1 A[i+1] = key python3.4 : def insertion_sort(sort_list): length = len(sort_list) for i in range(length)[1:]: key = sort_list[i] j = i...
2.4.1插入importbisectimportrandom#Use aconstant seed to ensure that#the samepseudo-random numbers#are usedeach time the loop is run.random.seed(1)print'New Pos Contents'print'--- --- ---'#Generaterandom numbers and#insert theminto a list in sorted#order.l =[]fori inrange(1, 15): ...
ls.insert(i,x) ls.pop(i) 取出并删除 ls.remove(x) 删除第一个x ls.reverse() 将ls中的元素反转 3.序列类型应用场景: item遍历 4.sorted排序 二 基本统计值实例 #CalStatisticsV1.py def getNum(): nums = [] iNumStr = input("请输入数字(回车退出):") while iNumStr !="": nums.append(e...
doubled = list1 * 3 # 输出: [1, 2, 3, 1, 2, 3, 1, 2, 3] # 检查列表是否包含特定元素 contains_2 = 2 in list1 # 输出: True contains_7 = 7 in list1 # 输出: False 通过熟练掌握上述列表的基本操作 ,您将在编写Python程序时具备高效处理序列数据的能力。接下来的章节将进一步探讨更高...
[0] left_nums = _quick_sorted([x for x in nums[1:] if x < pivot]) right_nums = _quick_sorted([x for x in nums[1:] if x >= pivot]) return left_nums + [pivot] + right_nums def quick_sorted(nums: list, reverse=False): nums = _quick_sorted(nums) if reverse: nums = ...
for j in range(i-1,-1,-1): if(raw_list[j]<=temp): break if(raw_list[j]>temp): raw_list[j],raw_list[j+1] = temp,raw_list[j] return raw_list #测试 data_test = [10,23,1,53,654,54,16,646,65,3155,546,31] sorted_list = insert_sort(data_test) print(sorted_list) ...
(" "))): schema = schema.add(f"word_{index}", IntegerType())returnAnalyzeResult(schema=schema)defeval(self, text: str):counts = {}forwordintext.split(" "):ifwordnotincounts: counts[word] =0counts[word] +=1result = []forwordinsorted(list(set(text.split(" "))): result.append...
res=sorted(d.items(),key=lambda x:x[1]) #根据字典value排序 # sorted做了两件事:1.循环 2.排序 循环的时候把每一个二维数组传给lambda, # lambda中返回二维数组的下标为1的元素作为key,sorted再根据这个key排序 #print(res) #sort l=[
class Solution: def insert(self, intervals: List[List[int]], newInterval: List[int]) -> List[List[int]]: if not intervals: return [newInterval] res = [] ins = self.helper(intervals,newInterval[0]) intervals.insert(ins,newInterval) for i in intervals: if not res or res[-1][1]...
def merge_intervals(intervals: list[list[int]]) -> list[list[int]]: # Sort the array on the basis of start values of intervals. intervals.sort() stack = [] # insert first interval into stack stack.append(intervals[0]) for curr in intervals[1:]: # Check for overlapping interval, #...