start)ifindex==-1:breakoccurrences.append(index)start=index+1returnoccurrences# 示例用法string="abracadabra"sub_string="a"occurrences=find_all_occurrences(string,sub_string)print(occurrences)# 输出 [0, 3, 5, 7, 10]
Finding All Occurrences Since theindex()only returns the first match to an object, you can use list comprehension, or generator expression if you need the positions of more matches in the list. Here is how: list_numbers=[3,1,2,3,3,4,5,6,3,7,8,9,10][ifori,ninenumerate(list_number...
12 批量修改代码 kepmap中找到main menu > edit > find > Select All occurrences 13 字体大小调整 代码字体调整 鼠标滚轮改变字体大小
) | L.count(value) -> integer -- return number of occurrences of value | | extend(...) | L.extend(iterable) -> None -- extend list by appending elements from the iterable | | index(...) | L.index(value, [start, [stop]]) -> integer -- return first index of value. | ...
Return the lowest index in S where substring sub is found, such that sub is contained within S[start:end]. Optional arguments start and end are interpreted as in slice notation. Return -1 on failure. S.find(sub[, start[, end]]) -> int ...
Return the lowest index in S where substring sub is found, such that sub is contained within S[start:end]. Optional arguments start and end are interpreted as in slice notation. Raises ValueError when the substring is not found. """ ...
Return the lowest index in S where substring sub is found, such that sub is contained within S[start:end]. Optional arguments start and end are interpreted as in slice notation. Return -1 on failure. """ return 0 用法:返回字符串sub的第一个索引,如果不存在这样的索引则返回-1,可定义搜索的...
old replaced by new. If the optional argument countisgiven, only the first count occurrences are replaced."""return "" def rfind(self, sub, start=None, end=None):"""S.rfind(sub [,start [,end]])->int Return the highest indexinS where substring subisfound, ...
If no elements are present, raises an IndexError. popleft() Remove and return an element from the left side of the deque. If no elements are present, raises an IndexError. queue — A synchronized queue class — Python 3.8.2 documentation https://docs.python.org/3/library/queue.html ...
In Python, indexes are coded as offsets from the front, and so start from 0: the first item is at index 0, the second is at index 1, and so on. Notice how we assign the string to a variable named S here. We’ll go into detail on how this works later (especially in Chapter ...