word_cnt={}forwordinword_list:ifword notinword_cnt:word_cnt[word]=0word_cnt[word]+=1print(word_cnt.items())# 按照词频排序 sorted_word_cnt=sorted(word_cnt.items(),key=lambda kv:kv[1],reverse=True)returnsorted_word_cnt inFile='in.txt'ifnot os.path.exists(inFile):print(f'file {i...
for number in range(0,len(list),3): list[number]=list[number].replace("\n","") list[number+1]=list[number+1].replace("\n","") if len(list)!=1487: str=list[number]+list[number+1]+list[number+2] new_list.append(str) else: str=list[number]+list[number+1] new_list.append...
:param word_list: :return: """ content = content.replace('\n', '').replace(',', ' ').replace('。', ' ').replace('\t', '').replace(' ', '') if word_list: for word in word_list: content = content.replace(word, '') content = content.strip('\r\n').replace(u'\u300...
long_words = [word for word in words if len(word) > 3] print(long_words) # 输出结果为 ['window', 'defenestrate'] ``` 在这个例子中,我们定义了一个名为 `long_words` 的新列表,它包含原始列表中所有长度大于3的单词。我们遍历了原始列表中的每个元素,并使用 `if` 条件过滤掉了长度小于等于3的...
word那里可以随便写什么,最好是有意义的表示列表里面的元素“!”是循环啊,每次肯定有的 靜待觀內 贡士 7 第一个for是循环用,for word in words指所有words里的变量都挑出來用一次,形象点來说就像你在农场手挑小鸡,从一号开始选择,选择到最后一个。 words是list,也就是那串字(农场里的鸡),而word是當下抓...
if key_a_list == df_response['statement']: count_a = count_a + 1 return count_a df_response['statement'] = df_response['statement'].apply(lambda x: " ".join([count(x) for word in x.split()])) key_a_list 由以下词组成:['think'、'college'、'education'、'help'、'better'...
= 0:list2[i] = list2[i - 1]content = list1[2] + ":\n" + list1[-4] # 报送内容if '否' in list1[-2]: # 备注remark = '有记录未上传,' + str(list1[-1])else:remark = '已上传'list3 = list2.tolist() # 需填入word中的表数据,由numpy数组转为list列表list3.append(str(...
fi= open("论语-网络版.txt", "r", encoding="utf-8") fo= open("论语-提取版.txt", "w") wflag= False #写标记 forline in fi: if "【" in line: #遇到【时,说明已经到了新的区域,写标记置否 wflag = False if "【原文】" in line: #遇到【原文】时,设置写标记为True wflag = True...
If the 286 separator is not found, return two empty strings and S. 287 """ 288 pass 289 290 def rsplit(self, sep=None, maxsplit=None): 291 """ 292 S.rsplit([sep [,maxsplit]]) -> list of strings 293 294 Return a list of the words in the string S, using sep as the 295...
even_number=[]foriinrange(1,101):ifi%2==0: odd_number.append(i)else: even_number.append(i)print'the odd number list is:','\n',odd_numberprint'the even number list is:','\n',even_number 执行结果 the odd number listis: