import re my_string = "Hello, world!" match = re.search(r"world", my_string) # 使用正则表达式 "world" 查找匹配的内容 if match: (tab)print("Match found!") # 如果找到匹配的内容，则输出 "Match found!" else: (tab)print("No match
def naive_string_match(T, P): n = len(T) m = len(P) for s in range(0, n-m+1): k = 0 for i in range(0, m): if T[s+i] != P[i]: break else: k += 1 if k == m: print s def naive_string_match(T, P): n = len(T) m = len(P) for s in range(0, n...
# d[p_idx - 1][s_idx - 1] is a string-pattern match # on the previous step, i.e. one character before. # Find the first idx in string with the previous math. while not d[p_idx - 1][s_idx - 1] and s_idx < s_len + 1: s_idx += 1 # If (string) matches (pattern...
这个方法将在字符串string的pos位置开始尝试匹配pattern(pattern就是通过re.compile()方法编译后返回的对象),如果pattern匹配成功,无论是否达到结束位置endpos,都会返回一个匹配成功后的Match对象;如果匹配不成功,或者pattern未匹配结束就达到endpos,则返回None。 参数说明: string:被匹配的字符串 pos:匹配的起始位置,可选...
import re def match_strings(string1, string2): pattern = re.compile(string1) match = pattern.match(string2) if match: return True else: return False string1 = "hello" string2 = "hello world" if match_strings(string1, string2): print("String 1 matches String 2") else: print("Strin...
re.match 只匹配字符串的开始,如果字符串开始不符合正则表达式,则匹配失败,函数返回 None,而 re.search 匹配整个字符串,直到找到一个匹配。实例 #!/usr/bin/python3 import re line = "Cats are smarter than dogs" matchObj = re.match( r'dogs', line, re.M|re.I) if matchObj: print ("match -...
分享一个match()使用的小demo: import re text = "Hello, World!" pattern = r"Hello" match = re.match(pattern, text) if match: matched_string = match.group() start_index = match.start() end_index = match.end() span_indices = match.span() print("Matched String:", matched_string) ...
if punct in string: num_puncts+=string.count(punct)print(num_puncts) --- 19 如果没有可支配的re模块,那就要用到上面的代码。但如果有re模块,则只需两行代码: import re pattern = r"[;.,–]" print(len(re.findall(pattern,string))) --- 19 本文讨论的是最常用的正则表达式模式,以及一些经常...
str01="browser uses BBC’s https://www.apple.com If you’re http://www.bt.cn thank you"print(re.findall(r"\b(?:http|https)[:/\w.]*(?:cn|com)\b",str01)) (2)finditer( ) 返回string中所有与pattern相匹配match对象的迭代,finditer适用的场景为捕获分组的场景; ...
intersection= list(set(prefix) & set(postfix))#得到相同前后缀ifintersection:returnlen(intersection[0])#得到最长前后缀returnodefkmp(t, p):#t: the string to check#p: patterni =0whilei < len(t) - len(p) + 1: match=Trueforjinrange(len(p)):ift[i+j] !=p[j]: ...