print(‘String does not contain substring’) The first argument is the string you are searching, and the second is the substring you are looking for. It also returns a Boolean. But these methods aren’t the only ones you can use to determine the existence of a substring in a string in ...
original_string = "Hello, world!" substring = "world" # 使用find()方法判断 if original_string.find(substring) != -1: print(f"The original string contains the substring '{substring}'.") else: print(f"The original string does not contain the substring '{substring}'.") 3. 判断原始字符...
"substring="Python"ifsubstringnotintext:print(f"The string '{text}' does not contain '{substring}'") 1. 2. 3. 4. 在上面的代码中,我们首先定义了一个字符串text和一个子字符串substring。然后使用not in操作符判断substring是否不在text中,如果是,则打印相应的提示信息。 2. 使用正则表达式进行判断 ...
print("The string does not contain 'CA'") In this example, theinoperator checks if the substring"CA"is present in thestatestring variable, which represents a U.S. state name. The code will output “The string contains ‘CA'” since “California” includes “CA”. Theinoperator is case-...
text="Learning Python is fun!"substring="Python"iftext.find(substring)!=-1:print(f'"{text}" contains "{substring}"')else:print(f'"{text}" does not contain "{substring}"') Copy 3. How to perform a case-insensitive string check?
if any(substring in my_str for substring in my_list): # 👇️ this runs print('The string contains at least one element from the list') else: print('The string does NOT contain any of the elements in the list') 1. 2.
Like rfind() but raises ValueError when the substring sub is not found. str.rpartition(sep) Split the string at the last occurrence of sep, and return a 3-tuple containing the part before the separator, the separator itself, and the part after the separator. If the separator is not found...
How to Check if a Python String Contains a Substring In this quiz, you'll check your understanding of the best way to check whether a Python string contains a substring. You'll also revisit idiomatic ways to inspect the substring further, match substrings with conditions using regular expressio...
Return the lowest index in the string where substring sub is found, such that sub is contained in the range [start, end]. Optional arguments start and end are interpreted as in slice notation. Return -1 if sub is not found. str.format(format_string, *args, **kwargs) ...
If the substring is present in the underlying string, then .find() returns the index at which the substring starts in the string. If the target string doesn’t contain the substring, then you get -1 as a result. So, an expression like string.find(substring) >= 0 would be equivalent ...