方法2:使用find函数实现contains的功能 s = "This be a string" if s.find("is") == -1: print "No 'is' here!" else: print "Found 'is' in the string."
class NoisyString(str): def __contains__(self, other): print('testing if "{0}" in "{1}"'.format(other, self)) return super(NoisyString, self).__contains__(other) ns = NoisyString('a string with a substring inside') 1. 2. 3. 4. 5. 6. 现在: >>> 'substring' in ns test...
Get Your Code:Click here to download the free sample codethat you’ll use to check if a string contains a substring. Take the Quiz:Test your knowledge with our interactive “How to Check if a Python String Contains a Substring” quiz. You’ll receive a score upon completion to help you...
The python str class has a __contains__() method that will check if a python string contains a substring. It will return true if it’s found and will return false if it’s not. You will notice that the method name is wrapped in two underscores. This prevents this method from being ...
Check if a Python string contains a substring using the in operator, find(), index(), or count(). Learn best practices and techniques with practical examples for efficient searching.
string = "Hello, world!" if string.find("world") != -1: (tab)print("String contains 'world'")结合start和end参数使用find函数进行字符串片段的提取。示例：提取字符串中的某个子字符串。string = "Hello, world! world is beautiful." start = 7 end = 12 extract = string[start:end] print...
Python中的contains()方法用于检查一个字符串是否包含另一个字符串,并返回一个布尔值。其使用方法如下: string.contains(substring) 复制代码 其中,string是要检查的字符串,substring是要检查的子字符串。 以下是一个示例: string = "Hello, World!" substring = "Hello" if string.contains(substring): print("...
"string2="Hello"ifstring1.find(string2)!=-1:print("string1包含string2")else:print("string1不包含string2") 1. 2. 3. 4. 5. 6. 7. 方法三:使用str.contains()方法 在Python中,还可以使用str.contains()方法来判断一个字符串是否包含另一个字符串。该方法返回一个布尔值,表示是否包含。
在第一种方法中,我们使用 in 和 not in 判断一个子串是否存在于另一个字符中,实际上当你使用 in 和 not in 时,Python解释器会先去检查该对象是否有__contains__魔法方法。 若有就执行它,若没有,Python 就自动会迭代整个序列,只要找到了需要的一项就返回 True 。
问Python是否有一个字符串'contains‘子字符串方法？EN如果这只是一个子串搜索，你可以使用string.find("...