s contains a=Trues contains A=Falses contains X=False Copy 2. Usingfind()to check if a string contains another substring We can also usestring find() functionto check if string contains a substring or not. This
方法2:使用find函数实现contains的功能 s = "This be a string" if s.find("is") == -1: print "No 'is' here!" else: print "Found 'is' in the string."
The python str class has a __contains__() method that will check if a python string contains a substring. It will return true if it’s found and will return false if it’s not. You will notice that the method name is wrapped in two underscores. This prevents this method from being ...
In this tutorial, you'll learn the best way to check whether a Python string contains a substring. You'll also learn about idiomatic ways to inspect the substring further, match substrings with conditions using regular expressions, and search for substri
"string2="Hello"ifstring1.find(string2)!=-1:print("string1包含string2")else:print("string1不包含string2") 1. 2. 3. 4. 5. 6. 7. 方法三:使用str.contains()方法 在Python中,还可以使用str.contains()方法来判断一个字符串是否包含另一个字符串。该方法返回一个布尔值,表示是否包含。
Python中的contains()方法用于检查一个字符串是否包含另一个字符串,并返回一个布尔值。其使用方法如下: string.contains(substring) 复制代码 其中,string是要检查的字符串,substring是要检查的子字符串。 以下是一个示例: string = "Hello, World!" substring = "Hello" if string.contains(substring): print("...
Python中的string.contains或string.indexof方法。 我想要做: if not somestring.contains("blah"): continue 1. 2. #1楼 Python是否有包含子字符串方法的字符串? 是的,但是Python有一个比较运算符,您应该改用它,因为该语言打算使用它,而其他程序员则希望您使用它。 该关键字位于in,用作比较运算符: ...
string = "Hello, world!" if string.find("world") != -1: (tab)print("String contains 'world'")结合start和end参数使用find函数进行字符串片段的提取。示例：提取字符串中的某个子字符串。string = "Hello, world! world is beautiful." start = 7 end = 12 extract = string[start:end] print...
Check if a Python string contains a substring using the in operator, find(), index(), or count(). Learn best practices and techniques with practical examples for efficient searching.
stringexample="Kiki"substring="ki"ifstringexample.find("ki")!=-1:print("We've found the string!")else:print("Oops, not found!") 1. 2. 3. 4. 5. 6. 其运行结果仍为: 复制 We've found the string! 1. 方法3:使用 Contains 方法 ...