#方法 1 Single Statement while True: print(1) #infinite 1 #方法 2 多语句 x = 0 while x < 5: print(x); x= x + 1 # 0 1 2 3 4 5 3、一行 IF Else 语句 好吧,要在一行中编写 IF Else 语句,我们将使用三元运算符。三元的语法是“[on true] if [expression] else [on false]”。
line = file1.readline() #readline()是读取一行 # 这里可以进行逻辑处理 file2.write('"'+line[:]+'"'+",") if not line : #如果行读取完成,就直接跳出循环 break #记住文件处理完成关闭文件是一个号习惯 file1.close() file2.close() 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 读文件有...
Strings can beconcatenatedto build longer strings using the plus sign and also they can bemultipliedby a number, which results in the continuous repetition of the string as many times as the number indicates. Also, if we want to find out thelengthof the string, we simply have to use thelen...
此报错可以忽略,这个是目前BOS平台的BUG。 报错提示2:unexpected token '<newline>' 不该出现换行的地方出现了换行,通常是需要打":"的地方没打,例如,if后面、方法定义后面等。 报错提示3:unexpected indent 缩进格式不对,通常是用空格敲了缩进,或者复制了网页的代码,格式混乱,重新用TAB键进行缩进。 报错提示4:un...
GL_LINE) glBegin(GL_TRIANGLES) glVertex2f(0.5, -0.5) glVertex2f(0.3, -0.3) glVertex2f(0.2, -0.6) # 结束绘制四边形 glEnd() # 清空缓冲区并将指令送往硬件执行 glFlush() # 主函数 if __name__ == "__main__": # 使用glut库初始化OpenGL glutInit() # 显示模式 GLUT_SINGLE无缓冲直接显...
line_color(:class:`~bokeh.core.properties.ColorSpec` ) : (default: 'black') 轮廓线颜色,默认:黑色。 line_dash(:class:`~bokeh.core.properties.DashPattern` ) : (default: []) 虚线,类型可以是序列,也可以是字符串('s...
def find_product_price(products, product_id): for id, price in products: if id == product_id: return price return None products = [ (143121312, 100), (432314553, 30), (32421912367, 150) ] print('The price of product 432314553 is {}'.format(find_product_price(products, 432314553)))...
# without code formattingdefthis_is_a_function_without_formatting(var_a, var_b, var_c, var_d, with_long_arguments):ifvar_a !=0andvar_b ==1andnot(var_corvar_d)andlen(with_long_arguments) <10: do_something() foo = this_is_a_function_without_formatting(var_a=1, var_b=2, var...
(palindrome_num % 10) reverse_order = ths * 1000 + hundred * 100 + ten * 10 + single if palindrome_num == reverse_order: print(palindrome_num,"是回文数") else: print(palindrome_num,"不是回文数") while 1: s1=int(input("请输入一个四位数:")) hui(s1) ch=input("是否继续判断(...