Python ask for user input again How to Take Continuous Input in Python – Another Example Let us see another example of how to take continuous input in Python. Step 1: Understand the Basic Input Function Python
1print("Hello World!")2print("Hello Again")3print("I like typing this.")4print("This is fun.")5print('Yay! Printing.')6print("I'd much rather you 'not'.")7print('I "said" do not touch this.') 你的Jupyter 单元格应该看起来像这样: 图片 不要担心如果你的 Jupyter 窗口看起来不...
return 'Reply hazy try again' elif answerNumber == 5: return 'Ask again later' elif answerNumber == 6: return 'Concentrate and ask again' elif answerNumber == 7: return 'My reply is no' elif answerNumber == 8: return 'Outlook not so good' elif answerNumber == 9: return 'Very ...
load(F) found = False rno = int(input("enter the roll number you want to update:")) for i in S: if rno == i[0]: print(f"the currrent name is {i[1]}") i[1] = input("enter the new name:") found = True break if found: print("Record not found") else: F.seek(0) ...
if try_again.lower() == "n": break ➑ input("\nPress Enter to exit.") 首先,向程序导入sys模块和random模块➊。sys模块使你能够访问具体的系统错误消息,同时允许你把IDLE窗口中的输出文字设置为醒目的红色。random模块使你可以随机地从存放名字和姓氏的元组中选择数据项。
input("?") print("Opening the file...") target = open(filename, 'w') print("Truncating the file. Goodbye!") target.truncate() print("Now I'm going to ask you for three lines.") line1 = input("line 1: ") line2 = input("line 2: ") ...
We want to input age which should be greater than 18 and less than 51, gender which should be either "Male" or "Female". If the user inputs an invalid value, the program should ask again for the input.Input until a valid response ...
This is because the REPL automatically prints return values—in this case, the value returned by input().The best practice when using input() is to assign it to a variable that you can use later in your code. For example, you can ask the user to type in their name. Assign input() ...
) 6 7 input("?") 8 9 print("Opening the file...") 10 target = open(filename, 'w') 11 12 print("Truncating the file. Goodbye!") 13 target.truncate() 14 15 print("Now I'm going to ask you for three lines.") 16 17 line1 = input("line 1: ") 18 line2 = input("line...
x = input("Enter a number:") try: x = float(x); y = False except: print("Wrong input, please try again.") print("Thank you!") Run Example » Exercise? What is the name of the method used to ask for user input? prompt() input() user()Submit Answer »❮...