如果想要获取一个数字的所有位数,有时我们可以直接使用列表解析,将数字的每一位存储在一个列表中。 defget_all_digits(number):# 将数字转化为字符串return[int(digit)fordigitinstr(abs(number))]# 示例num=123456digits=get_all_digits(num)print(f"The digits of the number{num}are{digits}.") 1. 2. ...
并添加到列表中digit=int(char)digits.append(digit)# 更新总和total_sum+=digitreturndigits,total_sum# 测试函数number=12345digits,sum_of_digits=get_digits_sum(number)print("Digits:",digits)print("Sum of digits:",sum_
AI代码解释 importrandomclassChar:letters='ABCDEFGHIJKLMNOPQRSTUVWXYZ'digits='0123456789'@classmethod defrandom_letter(cls):returnrandom.choice(cls.letters)@classmethod defrandom_digits(cls):returnrandom
>>> print(f"{42:b}") # Print 42 in binary 101010 >>> print(f"{42:032b}") # Print 42 in binary on 32 zero-padded digits 00000000000000000000000000101010 或者,您可以bin()使用号码作为参数调用: >>> >>> bin(42) '0b101010' 这个全局内置函数返回一个由二进制文字组成的字符串,它以前缀...
) | S.isdigit() -> bool | | Return True if all characters in S are digits | and there is at least one character in S, False otherwise. | | isidentifier(...) | S.isidentifier() -> bool | | Return True if S is a valid identifier according | to the language definition. | | ...
with open("pi_digits.txt") as file_object: contents = file_object.read() print(contents.rstrip()) 按行读取文件数据,可以如下使用: filename = 'pi_digits.txt' with open(filename) as file_object: lines = file_object.readlines() pi_string = "" for line in lines: pi_string += line....
int main() { printf("%ld\n", sizeof(PyLongObject)); return 0; } 上面的程序的输出结果如下所示: 上面两个结果是相等的,因此也验证了我们的想法。 从小整数池当中获取数据的核心代码如下所示: static PyObject * get_small_int(sdigit ival) ...
A numeric object of one type can be converted in another type using the following functions: Built-in FunctionDescription int Returns the integer object from a float or a string containing digits. float Returns a floating-point number object from a number or string containing digits with decimal...
第一行上标记十位数的数字之间都有 9 个空格,数字 1 前面有 13 个空格。22 到 24 行创建了一个包含此行的字符串,并将其存储在名为tensDigitsLine的变量中: # Print the numbers across the top of the board. print(tensDigitsLine) print(' ' + ('0123456789' * 6)) print() 要打印游戏板顶部的...
int("25") is not an integer literal because the integer value is created from a string.When you write large numbers by hand, you typically group digits into groups of three separated by a comma or a decimal point. The number 1,000,000 is a lot easier to read than 1000000....