Since theindex()only returns the first match to an object, you can use list comprehension, or generator expression if you need the positions of more matches in the list. Here is how: list_numbers=[3,1,2,3,3,4,5,6,3,7,8,9,10][ifori,ninenumerate(list_numbers)ifn==3]# List com...
复制 fig, axes = pylab.subplots(nrows=2, ncols=1, figsize=(20,15)) pylab.gray() inlier_idxs = np.nonzero(inliers)[0] plot_matches(axes[0], image_original_gray, image_warped_gray, source, destination, np.column_stack((inlier_idxs, inlier_idxs)), matches_color='b') axes[0].a...
to get fast response from the server use small sizetry:#Create an AF_INET (IPv4), STREAM socket (TCP)tcp_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)exceptsocket.error, e:print'Error occurred while creating socket. Error code: '+str(e[0]) +' , Error...
PATH_TO_CKPT = MODEL_NAME + '/frozen_inference_graph.pb' # List of the strings that is used to add correct label for each box. PATH_TO_LABELS = os.path.join('data', 'mscoco_label_map.pbtxt') NUM_CLASSES = 90 # ## Download Model # In[5]: opener = urllib.request.URLopener(...
for_stmt: 'for' exprlist 'in' testlist ':' suite ['else' ':' suite] Where exprlist is the assignment target. This means that the equivalent of {exprlist} = {next_value} is executed for each item in the iterable. An interesting example that illustrates this: for i in range(4):...
The join function works by using a delimiter to assemble the elements of a list into a string where each element is separated by that delimiter. We should have all we need to combine our final program. Let's try it out, and verify that everything is working: #!/usr/bin/python import...
db.things.find( { a : { $type : 16 } } ); // matches if a is an int 9)正则表达式 mongo支持正则表达式,如: db.customers.find( { name : /acme.*corp/i } ); // 后面的i的意思是区分大小写 10) 查询数据内的值 下面的查询是查询colors内red的记录,如果colors元素是一个数据,数据库将...
l1, d1 = sift.read_features_from_file(featlist[i]) l2, d2 = sift.read_features_from_file(featlist[j]) matches = sift.match_twosided(d1, d2) nbr_matches = sum(matches > 0) print 'number of matches = ', nbr_matches matchscores[i, j] = nbr_matches ...
Learn, how to find indices of matches of one array in another array in Python?ByPranit SharmaLast updated : December 28, 2023 Problem statement Suppose that we are given two numpy arrays, one contains unique values and another contains the same values as of first. We need to get the inde...
sort() alist2.sort() pos = 0 matches = True while pos < len(s1) and matches: if alist1[pos] == alist2[pos]: pos = pos + 1 else: matches = False return matches print(Solution2('abcde','edcbg')) def Solution3(s1,s2): c1 = [0]*26 c2 = [0]*26 for i in range(...