path, folder = os.path.split(path) if folder: folders.append(folder) else: if path: folders.append(path) break return list(reversed(folders)) path = "/home/user/Documents/example.txt" folder_names = get_folder_names(path) print("每个文件夹的名称:", folder_names) 运行以上代码,输出结果...
通过使用 pathlib 模块,我们可以更加直观地获取文件夹下的所有文件名。 frompathlibimportPathdefget_file_names(folder):folder_path=Path(folder)file_names=[file_path.nameforfile_pathinfolder_path.iterdir()iffile_path.is_file()]returnfile_names 1. 2. 3. 4. 5. 6. 在上面的代码中,Path类用于表示...
frompathlibimportPath# 从pathlib模块导入Path类# 获取用户的主文件夹路径user_folder=Path.home()# 输出用户文件夹路径print(f"用户的文件夹路径是:{user_folder}") 1. 2. 3. 4. 5. 6. 7. 代码解析: from pathlib import Path:导入pathlib库中的Path类。 user_folder = Path.home():使用Path.home()...
os.path.basenameoros.path.splitwon’t work in all the cases. If you are running a script on Linux and try to get windows path, it will fail. You can usenpath.basename()which will work in all the scenarios. That’s all about how to get filename from Path in Python...
file_path = os.path.join(root, file_name)# 获取文件的相对路径relative_path = os.path.relpath(file_path, base_path) file_size = os.path.getsize(file_path) file_update_time = os.path.getmtime(file_path) file_update_time = datetime.datetime.fromtimestamp(file_update_time) ...
示例1: addFolder ▲点赞 7▼ # 需要导入模块: from folder import Folder [as 别名]# 或者: from folder.Folder importgetPath[as 别名]defaddFolder(self, path):ifnotpathinself.folders: folder = Folder(path, self)iffolder.exists(): self.folders[folder.getPath()] = folder ...
folder.name= user.username folder.path = directory folder.user = user folder.save() os.makedirs(directory)exceptException, e:returnFalseelse:returnTrue # 需要导入模块: from models import Folder [as 别名]# 或者: from models.Folder importname[as 别名]defcreate_new_folder(user_id,father_id,name...
这些Path对象(实际上,WindowsPath或PosixPath对象,取决于你的操作系统)将被传递给本章介绍的几个与文件相关的函数。例如,以下代码将文件名列表中的名称连接到文件夹名称的末尾: >>>frompathlibimportPath>>>myFiles = ['accounts.txt','details.csv','invite.docx']>>>forfilenameinmyFiles:print(Path(r'C:\...
from modname import fa, fb, fc from modname import * 与第1种方法的区别:funcname 被直接导入到本地名字空间去了,所以它可以直接使用,而不需要加上模块名的限定* 表示,该模块的所有公共对象(public objects)都被导入到 当前的名称空间,也就是任何只要不是以”_”开始的东西都会被导入。 modname没有被定义...
python -m debugpy--listen|--connect[<host>:]<port>[--wait-for-client][--configure-<name><value>]...[--log-to<path>] [--log-to-stderr]<filename>|-m<module>|-c|--pid<pid>[<arg>]... Example From the command line, you could start the debugger using a specified port (5678...