fromdatetimeimportdatetime,timedeltadefget_days_in_month_with_datetime(year,month):# 创建一个指定年份、月份的第一天的日期对象ifmonth==12:next_month=1next_year=year+1else:next_month=month+1next_year=year first_day_of_next_month=datetime(next_year,next_month,1)last_day_of_current_month=first...
我们可以利用calendar模块中的monthrange函数来获取指定月份的天数,并结合datetime模块来计算月末日期。 importcalendarimportdatetimedefget_month_end(year,month):_,days_in_month=calendar.monthrange(year,month)returndatetime.date(year,month,days_in_month)# 示例year=2022month=3month_end=get_month_end(year,mon...
给出年月日计算该日是该年的第几天C语言#includeintmain(){intsum_day(intmonth,intday);intleap(intyear);intyear,month,day,days;printf("inputdate(year,month,day):");scanf("%d,%d,%d",year,month,day);... 继续访问 ? 数据库课程设计 c语言文件读写操作代码 html+css+js网页设计 ?写评论 ?
print('29天')else:print('28天')targetDay=datetime.date(year,month,day)?#将输入的日期专格式化成标准的日期 dayCount=targetDay-datetime.date(targetDay.year-1,12,31)?#减去上一属年最后一天 print('%s是%s年的第%s天。'%(targetDay,year,dayCount.days))结语：以上就是首席CTO笔记为大...
df['days_in_a_month']=df.apply(lambda x:extract_month_range(x['year'],x['month']),axis=1) 获取前一天日期 ? 代码语言:javascript 代码运行次数:0 运行 AI代码解释 # 获取前一天日期 df['yesterday']=df['datetime64']-datetime.timedelta(days=1) ...
timedelta(days=1) return date_list 2.获取所有月,返回一个列表: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 def getBetweenMonth(begin_date): date_list = [] begin_date = datetime.datetime.strptime(begin_date, "%Y-%m-%d") end_date = datetime.datetime.strptime(time.strftime('%Y-%m...
(n=0):91'''92getthe last day of monthfromtoday93nishow many months94'''95return"-".join("%s"%iforiingetyearandmonth(n))9697def getyearandmonth(n=0):98'''99getthe year,month,daysfromtoday100befor or after n months101'''102thisyear =int(year)103thismon =int(mon)104totalmon =...
范例1:采用Timestamp.days_in_month属性以找出给定Timestamp对象中的天数。 # importing pandas as pdimportpandasaspd# Create the Timestamp objectts = pd.Timestamp(2017,2,15,12)# Print the Timestamp objectprint(ts) 输出: 现在我们将使用Timestamp.days_in_month属性以找出给定Timestamp对象中的天数。
if i in (4, 6, 9, 11): days += 30 elif i == 2: if result: days += 29 else: days += 28 else: days += 31 days += day return days year, result = getyear() month = getmonth() day = getday(result, month) days = getdays(result,month,day) ...
dt=datetime.date(year,month,day) flag=True while True: dt+=datetime.timedelta(days=1) s="{}{:0>2d}{:0>2d}".format(dt.year,dt.month,dt.day) if s[:]==s[::-1]: if flag: print(s) flag=False if s[0]==s[2]==s[5]==s[7] and s[1]==s[3]==s[4]==s[6]: ...