isLeapYear(int year)确定给定的年份是否为闰年。 getActualMaximum public int getActualMaximum(int field) 1. 2. 3. 考虑到给定的时间值和 getFirstDayOfWeek、getMinimalDaysInFirstWeek、getGregorianChange 和 getTimeZone 方法的当前值,返回此日历字段可能具有的最大值。例如,如果此实例的日期是 2004 年 2 月 1 ...
# 提取月的总天数 defextract_month_range(year,month):'''提取这个月的总天数'''first_day_of_month,days_in_a_month=monthrange(int(year),int(month))returndays_in_a_month df['days_in_a_month']=df.apply(lambda x:extract_month_range(x['year'],x['month']),axis=1) 获取前一天日期 ?
employees=['Hisila', 'Shristi','Zeppy','Alina','Jerry'] df = pd.DataFrame({'Joined date': pd.to_datetime(list_of_dates)}, index=employees) df['Year'] = df['Joined date'].dt.year df['Month'] = df['Joined date'].dt.month df['Day'] = df['Joined date'].dt.day # 转化为...
在datetime中新建时间对象可以直接使用datetime(y, m,d,tzinfo)输入参数,用datetime.now()获得当前时间,通过datetime.fromtimestamp(ts)可以将时间戳ts转为时间对象,生成的datetime时间对象在获取属性时用到的语句类似dt.year,有year/month/day/hour/second/tzinfo等可以用。tzinfo是时区属性,datetime在时区相关处理时通...
res+= day - 1returnreselse:raiseValueError("day out of range") res+=_daysraiseValueError("month out of range") offset=0ifself.year < 1900orself.year >= 2050:raiseValueError('year out of range [1900, 2050)') yearIdx= self.year - 1900foriinrange(yearIdx): ...
>>> year='2019' >>> year.isdigit() True >>> vendor='F5' >>> vendor.isdigit() False >>> PI='3.1415926' >>> PI.isdigit() False >>> IP='1.1.1.1' >>> IP.isdigit() False isalpha()用来判断字符串的内容是否为英文字母,举例如下: ...
Don't be one of the leeches. Either stand out or kicked out. 先附上github地址: 下面是这个一百天计划里面的学习框架,我在这里放上来。 Day01~15 - Python语言基础 Day01 - 初识Python Python简介 - Python的历史 / Python的优缺点 / Python的应用领域 搭建编程环境 - Windows环境 / Linux环境 / MacO...
切换到统一的 PyCharm,免费获取所有核心 Community 功能,现在还提供内置 Jupyter 支持。 您可以照常升级到 PyCharm Community 2025.1,无需立即进行更改。下一版本将带来无缝迁移。无论哪种方式,您都可以保留所有内容并获得更多功能。 了解详情 PyCharm Community Edition ...
importdatetimeimportcalendardefget_date_of_next_month(form="%Y-%m-%d"):""" 获取下月开始结束日期 :param form 返回值显示格式 :return: str,date tuple """today = datetime.date.today() _, day = calendar.monthrange(today.year, today.month) ...
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