defget_day_of_day(n=0):'''ifn>=0,date is larger than todayifn<0,date is less than today date format="YYYY-MM-DD"'''if(n<0):n=abs(n)returndate.today()-timedelta(days=n)else:returndate.today()+timedelta(days=n)defget_days_of_month(year,mon):'''getdaysofmonth'''returncalen...
is_holiday=calendar.is_holiday(today)print(is_holiday)#返回 True 或 Falseon_holiday, holiday_name=calendar.get_holiday_detail(today)print(on_holiday, holiday_name)#返回 True 或 False,节假日名称#获取某天的节气end_of_day = datetime.date(2024, 8, 31) term=calendar.get_solar_terms(today, end...
from datetime import date def calculate_age(born): today = date.today() try: birthday = born.replace(year=today.year) except ValueError: birthday = born.replace(year=today.year, month=born.month + 1, day=1) if birthday > today: return today.year - born.year - 1 else: return today....
fromdatetimeimportdatetimedefget_start_of_week():today=datetime.now()# 获取今天的日期# 计算本周第一天(星期一)start_of_week=today-timedelta(days=today.weekday())returnstart_of_week# 测试代码if__name__=="__main__":start_date=get_start_of_week()print(f"本周第一天是:{start_date.strftime...
year=datetime.date.today().yearprint(year) Output:202119在 Python 中找到星期几importpendulum dt= pendulum.parse('2021-05-18')print(dt.day_of_week) dt= pendulum.parse('2021-05-01')print(dt.day_of_week) dt= pendulum.parse('2021-05-21')print(dt.day_of_week) ...
df['today']=datetime.date.today() 提取日期实体 ? 代码语言:javascript 代码运行次数:0 运行 AI代码解释 # 提取日期实体 df['day']=df['datetime64'].dt.day #天 df['weekday']=df['datetime64'].dt.weekday #周 df['month']=df['datetime64'].dt.month #月 ...
There are a number of ways we can take to get the current date. We will use thedateclass of thedatetimemodule to accomplish this task. Example 1: Python get today's date fromdatetimeimportdate today = date.today()print("Today's date:", today) ...
dt=dateutil.parser.parse('April 29')#会取当前年# datetime.datetime(2020, 4, 29, 0, 0)dt=dateutil.parser.parse("Today is January 1, 2047 at 8:21:00AM",fuzzy_with_tokens=True) dateutil的parser类用于更方便地从字符串解析为datetime对象,parser.parse(string)可以从各种类型的字符串例如一句...
/usr/bin/envpythonimportdatetimespring=datetime.datetime(2014,1,31,0,0,0)#春节日期today=datetime.datetime.now()... 继续访问 python代码实现“今天是今年的第几天” python代码实现“今天是今年的第几天”**#代码如下:list_day_runnian=[0,31,29,31,30,31,30,31,31,30,31,30,31]year=int(input...
在您的例子中,我只使用loc来查找今天的值,您可以使用pd.to_datetime('today')作为比较值: >>> df2.loc[pd.to_datetime(df2.Date) == pd.to_datetime('today').strftime("%Y-%m-%d")] Date Main Dessert Menu0 18/04/2021 Sunday Roast Ice Cream a ...