major_axis=pd.date_range('20130101', periods=3), minor_axis=['first', 'second']) # 结果 <class 'pandas.core.panel.Panel'> Dimensions: 4 (items) x 3 (major_axis) x 2 (minor_axis) Items axis: A to D Major_axis axis: 2013-01-01 00:00:00 to 2013-01-03 00:00:00 Minor_ax...
# coding=utf-8importtimeimportdatetime # 今天日期 today=datetime.date.today()# 昨天时间 yesterday=today-datetime.timedelta(days=1)# 明天时间 tomorrow=today+datetime.timedelta(days=1)acquire=today+datetime.timedelta(days=2)# 昨天开始时间戳 yesterday_start_time=int(time.mktime(time.strptime(str(yest...
>>>arrow.get(datetime.utcnow())<Arrow [2024-06-13T09:14:15.099808+00:00]>>>arrow.get(datetime(2024,6,13),'Asia/Shanghai')<Arrow [2024-06-13T00:00:00+08:00]>>>fromdateutilimporttz>>>arrow.get(datetime(2024,6,13), tz.gettz('Asia/Shanghai'))<Arrow [2024-06-13T00:00:00+...
defget_this_week_start_and_end_day():today=date.today()returntoday-timedelta(days=today.weekday())defget_past_week_start_and_end_day():today=date.today()# threeWeeksAgo_start=today-timedelta(days=today.weekday()+21)# threeWeeksAgo_end=today-timedelta(days=today.weekday()+15)# twoWeek...
today=datetime.date.today()print("当前日期是这周的第几天(星期一==0/周日==6):",today.weekday())# 当前日期是这周的第几天(星期一==0/周日==6):2print("当前日期是这周的第几天(星期一==1/周日==7):",today.isoweekday())# 当前日期是这周的第几天(星期一==1/周日==7):3 ...
obj_b=datetime.datetime.now()ifobj_b >obj_a: late= obj_b.timestamp() -obj_a.timestamp()print(f"obj_b is late than b: {late}") 二、Shell时间操作 2.1 基础操作 # 获取当前时间,并输出成指定格式 # 有引号是因为有空格,没有空格用不用引号都一样date+"%Y-%m-%d %H:%M:%S"# 获取昨天...
weekday() day_num_target = weekdays.index(dayname) days_ago = (7 + day_num - day_num_target) % 7 if days_ago == 0: days_ago = 7 target_date = start_date - timedelta(days=days_ago) return target_date def last_friday(): print(datetime.today()) print(get_previous_byday('...
def get_previous_byday(dayname, start_date=None): if start_date is None: start_date = datetime.today() day_num = start_date.weekday() day_num_target = weekdays.index(dayname) days_ago = (7 + day_num - day_num_target) % 7 ...
>>> round(a, -1) 1627730 >>> round(a, -2) 1627700 >>> 1. 2. 3. 4. 5. 6. 不要将舍入和格式化输出搞混淆了。如果你的目的只是简单的输出一定宽度的数,你不需要使用round()函数。而仅仅只需要在格式化的时候指定精度即可, ...
from datetime import datetime, timedelta today = datetime.now() one_week_ago = today - timedelta(weeks=1) print(f"Today's date: {today}") print(f"One week ago: {one_week_ago}") When you run this code, you'll get an output similar to this: Today's date: 2022-09-30 16:50:...