我们可以使用inspect.getframeinfo()函数来获取当前代码的堆栈信息,然后从中提取出当前文件的路径。 importinspect current_file=inspect.getframeinfo(inspect.currentframe()).filename current_dir=os.path.dirname(os.path.abspath(current_file))print(current_dir) 1. 2. 3. 4. 5. 上述代码中,inspect.current...
privatevoidButton_Click(object sender,RoutedEventArgs e){string[]strArr=newstring[2];//参数列表string sArguments=@"main.py";//这里是python的文件名字strArr[0]="2";strArr[1]="3";RunPythonScript(sArguments,"-u",strArr);}//调用python核心代码publicstaticvoidRunPythonScript(string sArgName,st...
语法:fileObject.read() 代码语言:javascript 代码运行次数:0 运行 AI代码解释 fo=open("foo.txt","r",encoding="UTF-8")print("文件名为: ",fo.name)line=fo.read()#不指定字符节读取所有print(line)fo.close()# 关闭文件 # 如下:#C:\Python35\python.exeD:/linux/python/all_test/总练习.py # ...
os.path.abspath(file_path))print("File exists: ", os.path.exists(file_path))print("Parent directory: ", os.path.dirname(file_path))print("Parent directory: {} | File name: {}".format(
FILE_TYPE_USER: EFFECTIVE_MODE_NO_NEED, # User-defined file FILE_TYPE_FEATURE_PLUGIN: EFFECTIVE_MODE_NO_REBOOT # Feature package } # File name extension of the deployment file, which is used for file name verification FILE_EXTENSION = { FILE_TYPE_SOFTWARE: ('.cc', ), FILE_TYPE_CFG: ...
importosdefget_file_path(filename):current_dir=os.getcwd()# 获取当前工作目录file_path=os.path.join(current_dir,filename)# 拼接文件名和路径returnfile_path# 使用示例filename="example.txt"path=get_file_path(filename)print("文件路径:",path) ...
这个配方的命令行处理程序接受三个位置参数,EVIDENCE_FILE,IMAGE_TYPE和CSV_REPORT,分别代表证据文件的路径,证据文件的类型和所需的 CSV 报告输出路径。这三个参数被传递给main()函数。 if__name__ =='__main__': parser = argparse.ArgumentParser(
open("document.docx", "rb") as docx_file: result = mammoth.convert_to_html(docx_file) ...
inspect.isgetsetdescriptor(object):是否为getset descriptor inspect.ismemberdescriptor(object):是否为member descriptor inspect的getmembers()方法可以获取对象(module、class、method等)的如下属性: Type Attribute Description Notes module __doc__ documentation string __file__ filename (missing for built-...
from contextlib import contextmanager @contextmanager def managed_file(filename, mode='r'): try: f = open(filename, mode) yield f finally: f.close() # 使用with语句简化文件操作 with managed_file('example.txt', 'w') as f: f.write('Hello, World!') 这一章通过剖析面向对象编程中的SOLI...