// Python/marshal.cvoidPyMarshal_WriteObjectToFile(PyObject *x, FILE *fp, int version){char buf[BUFSIZ]; WFILE wf;if (PySys_Audit("marshal.dumps", "Oi", x, version) < ) {return; /* caller must check PyErr_Occurred() */ }memset(&wf, , sizeof(wf)); wf.fp = fp; ...
# {'first_name': <property object at 0x0000000002E7FAE8>, '__dict__': <attribute '__dict__' of 'Person' objects>, '__init__': <function Person.__init__ at 0x0000000002E8D048>, '__doc__': None, '__weakref__': <attribute '__weakref__' of 'Person' objects>, '__modul...
FunctionCaller+ ...+call_function_by_name(function_name: str) : NoneFunction+ ...+__call__() : NoneSomeFunction+ ...+__call__() : NoneAnotherFunction+ ...+__call__() : None 5. 状态图 下面是一个使用mermaid语法标识的状态图,展示了函数调用时的状态转换。 ReadyFunction Name ValidFun...
示例6: get_caller_locals ▲点赞 6▼ # 需要导入模块: import inspect [as 别名]# 或者: from inspect importgetargvalues[as 别名]defget_caller_locals(decorators=0):'''returns the locals of the calling function. from http://pylab.blogspot.com/2009/02/ python-accessing-caller-locals-from.html ...
True如果object参数显示为可调用 False则返回,否则返回。如果返回true,则调用仍然可能失败,但如果调用失败,则调用对象将永远不会成功。请注意,类是可调用的(调用类会返回一个新实例); 如果实例的类具有__call__()方法,则它们是可调用的。 版本3.2中的新功能:此功能首先在Python 3.0中删除,然后在Python 3.2中恢复...
Caller(调用): # 创建一个空的list和一个当前对象的引用list result, candidates = list(), [self] # 遍历candidates,一开始他仅仅包含一个元素 while candidates: # 获取并删除list中最后位置上的candidate node = candidates.pop() # 获取candidate到obj之间的距离 distance = node._get_dist(obj) # 如果距...
pythonapi.PyFrame_LocalsToFast(py_object(f), 0) >>> def enclose(): ... x = 10 ... ... def test(): ... nonlocal(x = 1000) ... ... test() ... print x >>> enclose() 1000 这种实现通过 _getframe() 来获取外部函数堆栈帧名字空间,存在⼀一些限制.因为拿到是调⽤用者, ...
(filename, line_number, function_name, lines, index) print(hello()) # (<frame object at ...
defget_object(cls, context, fields=None, **kwargs):"""Fetch a single object Return the first result of given context or None if the result doesn't contain any row. Next, convert it to a versioned object. :param context: :param fields: indicate which fields the caller is interested in...
https://stackoverflow.com/questions/13699283/how-to-get-the-callers-filename-method-name-in-python 1 2 3 4 5 6 7 defdefault_file_name(self): importinspect frame=inspect.stack()[2] module=inspect.getmodule(frame[0])# 根据数据帧取出调用的模块 ...