(1)定义一个递归的函数,用于生成所有子集: def generate_subsets(myset): if not myset: return [[]] item = myset.pop() all_subsets = generate_subsets(myset) return all_subsets + [subset+[item] for subset in all_subsets] 1. 2. 3. 4. 5. 6. 在Python中,list.pop()函数用于弹出list...
import itertools def generate_subsets(myset): all_subsets = [] for i in range(len(myset) + 1): subsets = itertools.combinations(myset, i) all_subsets.extend(subsets) return all_subsets # 示例 myset = {1, 2, 3} subsets = generate_subsets(myset) for subset in subsets: print(subset...
编写一个程序来生成给定整数集合的大小为n的所有子集。定义函数generate_subsets()，有两个参数input_set(整数集合)和n。在函数内部，生成input_set的大小为n的所有子集，并以列表返回。示例输入 1 2 3 2 示例输出 [{1, 2}, {1, 3}, {2, 3}]解释:{1,2,3}的大小为2的子集为{1,2}，{1,3}和{2...
res.append(combo)returnresdefPowerSetsRecursive(items):#2,回归方法"""Use recursive call to return all subsets of items, include empty set"""iflen(items) ==0:# if the lsit is empty, return the empty listreturn[[]] subsets = [] first_elt = items[0]# first elementrest_list = items...
A power set is the set of all subsets of a collection of values. import memory_graph as mg def get_subsets(subsets, data, i, subset): mg.block(mg.show, mg.get_call_stack()) if i == len(data): subsets.append(subset.copy()) return subset.append(data[i]) get_subsets(subsets, ...
3. Sort and iteratively generate n subset with n-1 subset, O(n^2) and O(2^n) 90Subsets IIPython1. DFS Recursion with duplicate check, O(2^n) and O(2^n) 2. Recursion on a binary number, O(2^n) and O(2^n) 3. Sort and iteratively generate n subset with n-1 subset, note...
subsets= [i fori in i_subset] # print(subsets) foreach in subsets: # print(each) ifeach!=[] and each!=p and len(each)<k: -="":=""break=""c1="createC1(dataSet)"ckc=""d="[set(var)"def=""for=""if=""in=""k=""l=""not=""return=""suppdata="scanDataSet(D,"t=""...
Given a collection of integers that might contain duplicates, nums, return all possible subsets.def subsets2(nums): res = [[]] for num in nums: res += [ i + [num] for i in res if i + [num] not in res] return res def subsets_recursive2(nums): lst = [] result = [] nums...
I pick the solution which generate all possible subsets (2^n) and then yield just those that sum is equal to the number. I have a problem with the condition. Code:def allSum(number): #mask = [0] * number for i in xrange(2**number): subSet = [] for j in xrange(number): #i...
def subsetsWithDup(self, nums): """ :type nums: List[int] :rtype: List[List[int]] """ res = [] nums.sort() def dfs(i, path): res.append(path) for k in range(i,len(nums)): if k>i and nums[k-1]==nums[k]: continue dfs(k+1,path +[nums[k]]) dfs(0,[]) return...