Python Leap Year #The test case is passing 4/6. I don't know what is wrong with my code, please help year = int(input()) if year % 4 == 0: if year % 100 == 0: if year % 400 == 0: print("Leap year") else: print("Not a leap year") else: print("Not a leap year...
6.程序实现的功能:输人某年某月某日,判断这一天是这一年的第几天,Python代码如下: d e f leap(year):$$ l e a p = 0 $$$ i f ( y e a r \% 4 0 0 = = 0 ) o r ( ( y e a r \% 4 = = 0 ) a n d ( y e a r \% 1 0 0 ! = 0 ) ) : $$$ l e a ...
= 0 instead of == 0 to output a print command. Here's what I came up with. I didn't see that step 2 said "IS a leap year" which stumped me for a while. year = int(input()) #your code goes here if year % 4 != 0: print("Not a leap year") elif year % 100 != 0:...
year, month, day = int(nums[0]), int(nums[1]), int(nums[2]) # 得到的年月日转成整数 int assert (0 <= year <= 9999) # 年份不在0-9999范围内 报错 assert (0 <= month <= 12) # 月份不在1-12范围内 报错 days = function1(year, month, day) if month in [1, 3, 5, 7, ...
1、定义一个is_leap(year)函数,该函数可以判度year是否为闰年。若是闰年,则返回True;否则返回False。 import sys def is_leap(year): year = int(year) if year % 4 != 0: return False elif year % 100 != 0: return True elif year % 400 != 0: ...
Python程序LeapYear源码 import math def valid(month,day,year):if day>31:return False elif month==2:if leap(year):if day <=29:return True else:return False else:if day<=28:return True else:return False elif month==4 or 6 or 9 or 11:if day>31:return False else:return True else:r...
The use of or between these conditions ensures that if either condition is true, the year is considered a leap year. 4) Using Datetime Module Logic Of Code Explained: The function try to create a“datetime” object for February 29 of the given year using “datetime(year, 2, 29)” It ...
defisLeapYear(y):# 判断闰年的函数if(y%4==0andy%100!=0)ory%400==0:# 是闰年 返回TruereturnTrueelse:returnFalse# 否则返回Falsedeffunction1(i,j,k):# 计算给定日期是那一年的第几天leap_year=[31,29,31,30,31,30,31,31,30,31,30,31]no_leap_year=[31,28,31,30,31,30,31,31,30,31...
calendardefaultfunctionsorttime 例1:有四个数字:1、2、3、4能组成多少个互不相同且无重复的数字的三位数?各是多少?审题: 1.去重 2.计算总数程序代码:方法1: py3study 2020/01/07 6000 每四年就出现一次的bug,凶手竟是他? python编程算法网络安全 2020年的开年,新型冠状病毒来得猝不及防,大家过了一个与...
#简单的格式: def functionname(参数...,*args,**kwargs): 代码块 # *args :args是常用名,不是必须的,可以自定义成其他,*是必须的,他用来接收其他未被匹配的多余 # 的值。然后将它们保存在以args为变量名的元祖中。 这个又称之为可变参数 # **kwargs: kwargs也是常用名,也不是必须的,可以自定义成...