my_list=["apple","orange","banana","watermelon"]deffind_longest_string(lst):longest_string=""forstringinlst:iflen(string)>len(longest_string):longest_string=stringreturnlongest_string result=find_longest_string(my_list)print("The longest string is:",result) 1. 2. 3. 4. 5. 6. 7. 8...
addresses=["123 Elm Street","531 Oak Street","678 Maple Street"]street="Elm Street"#The top2methods to checkifstreetinanyofthe itemsinthe addresses list #1-Using the find methodforaddressinaddresses:ifaddress.find(street)>=0:print(address)#2-Using the"in"keywordforaddressinaddresses:ifstree...
record[i+1][j+1]=record[i][j]+1ifrecord[i+1][j+1]>maxNum:maxNum=record[i+1][j+1]p=i # 匹配到下标i # 返回 子串长度,子串returnmaxNum,s1[p+1-maxNum:p+1]defprintMatrixList(li):# 打印多维list row=len(li)col=len(li[0])foriinrange(row):forjinrange(col):print(li[i][...
Write a Python program to determine the list with the maximum number of unique elements and the one with the minimum using lambda. Write a Python program to find the sublist with the longest and shortest total string length when elements are concatenated, using lambda....
Write a function to find the longest concatenated string that is a palindrome. def longest_palindrome_concatenation(str_list): # Your code here pass # Example usage: strings = ["aba", "cd", "xy", "ba"] result = longest_palindrome_concatenation(strings) print(result) In programming, conver...
If you have any keys you’d recommend, let us know in the comments. As it turns out, manipulating strings isn’t always easy. I learned that the hard way when I started the Reverse a String in Every Language series.Sort a List of Strings in Python in Descending Order...
def reverseString(self, s: List[str]) -> None: s.reverse() 1. 2. 3. 解法二(前后对称交换): class Solution: def reverseString(self, s: List[str]) -> None: total = int(len(s)) count = int(total/2) for i in range(count): ...
self._data = list(args) ... ... def __iter__(self): ... for x in self._data: ... yield x >>> d = Data(1, 2, 3) >>> for x in d: print x 1 2 3 编译器魔法会将包含 yield 的⽅方法 (或函数) 重新打包,使其返回 Generator 对象.这样⼀一来,就 ⽆无须废⼒力...
# leetcode-121: class Solution: def maxProfit(self, prices: List[int]) -> int: if len(prices) < 2: return 0 prof = 0 min_p = prices[0] for i in prices: min_p = min(i, min_p) prof = max(i - min_p, prof) return prof # 暴力解法(超时): class Solution: def maxProfit(...
def find_longest_string_ignore_empty(strings): # 过滤掉空字符串 non_empty_strings = [s for s in strings if s] if not non_empty_strings: return "" return max(non_empty_strings, key=len) # 示例集合包含空字符串 string_list_with_empty = ['apple', '', 'banana', 'strawberry', ''...