方法1:独立函数法 deflist_find(item_list, find_item): if find_item in item_list: return item_list.index(find_item) return -1item_list=[1,2,3]print(list_find(item_list,1),list_find(item_list,4)) AI代码助手复制代码 缺点:代码太多,麻烦 方法2:if三元表达式(本质同上) item_list.index(...
Given a Python list, we have to find the index of an item in a list. Submitted by Nijakat Khan, on July 15, 2022 To find the index of the specific element from the list, we can use the following methods:1) Using index() MethodThe index() method is used to find the index ...
Python中是有查找功能的,五种方式:in、not in、count、index,find 前两种方法是保留字,后两种方式是列表的方法。 下面以a_list = ['a','b','c','hello'],为例作介绍: string类型的话可用find方法去查找字符串位置: a_list.find('a') 如果找到则返回第一个匹配的位置,如果没找到则返回-1,而如果通过...
item_index = np.where(np_array==item) print item_index # Out: (array([0, 2, 6], dtype=int64),) 1. 2. 3. 4. 5. 6. 7. 它是清晰易读的解决方案。 四、zip 具有该zip功能的所有索引: get_indexes = lambda x, xs: [i for (y, i) in zip(xs, range(len(xs))) if x == y...
To find the index of an item in a Python list, you can use thelist.index()methodby passing the item whose index is to be found. If the item exists in the list, it returns the index;ValueError, otherwise. Syntax list.index(x[, start[, end]]) ...
deffind_in_nested_list(nested_list,target):foriteminnested_list:ifisinstance(item,list):# 如果元素是列表,则递归查找result=find_in_nested_list(item,target)ifresultisnotNone:returnresultelifitem==target:returnitemreturnNone 1. 2. 3. 4. ...
Find if an element exists in the list using a loopPython offers a straightforward approach that involves iterating over each item in the list and checking for a match to find if an element exists in the list using a loop. This method is particularly useful when you need to perform ...
To find the index of an element in the list in Python, we can also use theforloop method. The code is: consonants=["b","f","g","h","j","k"]check="j"position=-1foriinrange(len(consonants)):ifconsonants[i]==check:position=ibreakifposition>-1:print("Element's Index in the ...
Methods to Find a String in a List 1. Using theinOperator (Fastest for Membership Testing) Theinoperator is the most straightforward way to check if a string is present in a list. It is also the fastest method for membership testing, making it a great choice for simple checks. Here’s...
也就是列表元素为2时，lt[i]!=val为false，进入下一次循环，此时k=1，i=2，lt[2]!=val (备注...