if char in string: print(f"The character '{char}' is found in the string.") else: print(f"The character '{char}' is not found in the string.") 输出结果将是:The character 'a' is not found in the string.,因为字符a并不存在于字符串中。 问题2:如何在Python中判断一个字符串是否包含...
find()方法返回字符在字符串中的索引位置,如果不存在,则返回-1。我们可以判断返回值是否为-1来判断字符是否不在字符串中。下面是示例代码: character='a'string='Hello, World!'ifstring.find(character)==-1:print(f"The character '{character}' is not in the string.")else:print(f"The character '{c...
Python中的字符串类提供了一个find()方法,可以用于查找一个字符在字符串中的位置。如果找到了字符,则返回其在字符串中的索引值;如果找不到,则返回-1。可以通过以下方式使用: char='a'string='hello world'ifstring.find(char)!=-1:print(f'The character{char}is present in the string')else:print(f'The...
it was pretty easy to find the index to change as there are few characters in the string.How are we supposed to know which character to change if the string is larger?
在Python中,可以使用字符串的find()方法来查找指定字符。find()方法返回指定字符在字符串中第一次出现的位置,如果没有找到则返回-1。 以下是使用find()方法查找指定字符的示例: string = "Hello, World!" character = "o" index = string.find(character) if index != -1: print(f"The character '{...
a nice string representation of the object. | If the argument is a string, the return value is the same object. | | Method resolution order: | str | basestring | object | | Methods defined here: | | __add__(...) | x.__add__(y) <==> x+y | | __contains__(...) | x...
Find character indices in string.Write a Python program to print the index of a character in a string.Sample Solution:Python Code:# Define a string 'str1'. str1 = "w3resource" # Iterate through the characters of the string using enumeration. # 'index' contains the position of the ...
Please enter a character A-Z:A Aispresentinthelist Copy Methods to Find a String in a List 1. Using theinOperator (Fastest for Membership Testing) Theinoperator is the most straightforward way to check if a string is present in a list. It is also the fastest method for membership testin...
2. Usingfind()to check if a string contains another substring We can also usestring find() functionto check if string contains a substring or not. This function returns the first index position where substring is found, else returns -1. ...
# print(aa.ljust(50,'0000')) # TypeError: The fill character must be exactly one character long # 以上是一个错误,原因是:填充字符必须正好是一个字符长 print(aa.rjust(50,'*'),1111111) # 结果:beijing Tami KEJI YouXian GongSi*** 1111111 ### 方法返回指定长度的...