# 需要导入模块: from snisi_core.models.Periods import MonthPeriod [as 别名]# 或者: from snisi_core.models.Periods.MonthPeriod importfind_create_by_date[as 别名]defboundaries(cls, date_obj):date_obj = normalize_date(date_obj, as_aware=True) start = date_obj.replace(day=29, h...
1)# 上月最后一天premonthlastday=firstday-timedelta(days=1)# 返回上月的今天returndatetime(premonthlastday.year,premonthlastday.month,dt.day)# 最长公共子序列 (The Longest Common Subsequence)子串要求字符必须是连续的,但是子序列就不
:] # rows a[:, ~np.isnan(a).any(axis=0)] # columns beta = np.nan_to_num(num / denom, nan=0, posinf=0, neginf=0) # drop_dup, reindex and fill df['sharpeday'] = df.index.to_series().apply(lambda x: x.year*10000+x.month*100+x....
Map() times from original call and as_completed() from first call to next(). As_completed() fails if next() is called too late, even if all threads are done. Exceptions that happen inside threads are raised when map iterator's next() or Future's result() are called. Future's ...
定义函数:find_first_sunday函数接受一个年份作为参数,并查找该年每个月的第一个星期天。 初始化月份:我们从1月开始遍历到12月。 设置日期为每月的第一天:使用datetime.date(year, month, 1)创建一个日期对象,表示每月的第一天。 计算到第一个星期天的天数:date.weekday()返回星期几(星期一是0,星期天是6)。
# sftp://[username[:password]@]hostname[:port] # (2) Do not add a trailing slash at the end of the file server path. FILE_SERVER = 'sftp://sftp_user:sftp_pwd@xx.xx.xx.xx' # TIME_SN is a string consisting of the year, month, day, hour, minute, and second. TIME_SN = '...
该对象包括当前时刻的年、月、日、小时、分钟、秒和微秒。您还可以通过使用datetime.datetime()函数 ➌ 来检索某个特定时刻的datetime对象,向其传递表示年、月、日、时和您想要的时刻的整数。这些整数将存储在datetime对象的year、month、day、hour、minute、属性中 ➍。
defprevious_day(dtToday):returndtToday - pd.DateOffset(days=1) This returns2017-03-03. However, this business day is not available in my range of dates (dfDates). I am therefore looking for a robust way to find the date that is the closest to the previous day/month/year/...
该对象包括当前时刻的年、月、日、小时、分钟、秒和微秒。您还可以通过使用datetime.datetime()函数 ➌ 来检索某个特定时刻的datetime对象,向其传递表示年、月、日、时和您想要的时刻的整数。这些整数将存储在datetime对象的year、month、day、hour、minute、属性中 ➍。
from datetime import datetime def day_of_year(year, month, day): return (datetime(year, month, day) - datetime(year, 1, 1)).days + 1 assert day_of_year(2014, 1, 10) == 10 数据类型转换 将字符串:"k:1|k1:2|k2:3|k3:4",处理成python字典:{k:1, k1:2, ... } def string...