def find_duplicate_characters_set(input_string): unique_chars = set() duplicates = set() for char in input_string: if char in unique_chars: duplicates.add(char) else: unique_chars.add(char) return list(duplicates) input_str = "hello world" result_set = find_duplicate_characters_set(inpu...
def find_duplicate_characters(input_string): char_count = {} duplicates = [] for char in input_string: if char in char_count: if char not in duplicates: duplicates.append(char) else: char_count[char] = 1 return duplicates input_str = "hello world" result = find_duplicate_characters(in...
deffind_duplicates(strings):count_dict={}duplicates=[]forstringinstrings:ifstringnotincount_dict:count_dict[string]=1else:count_dict[string]+=1ifcount_dict[string]==2:duplicates.append(string)returnduplicates strings=["apple","banana","apple","orange","banana","mango","apple"]result=find_d...
AI检测代码解析 fromcollectionsimportCounterdefget_substrings(string,n):substrings=[]foriinrange(len(string)-n+1):substrings.append(string[i:i+n])returnsubstringsdefcount_substrings(substrings):returnCounter(substrings)deffind_duplicates(count):return[substrforsubstr,countincount.items()ifcount>1]...
duplicates = [] # 遍历集合中的元素 for char in chars_set: # 统计字符在字符串中出现的次数 count = string.count(char) # 如果出现次数大于1,则说明是重复字符 if count > 1: duplicates.append(char) return duplicates # 调用函数并打印结果 string = "abracadabra" print(find_duplicate_chars(string...
在Python中查找字符串中最长的重复片段可以通过以下步骤实现: 1. 定义一个函数`find_longest_duplicate(string)`来查找最长的重复片段。 2. 初始化一个空列表`d...
SetsFast lookups without duplicatesIdeal for situations where uniqueness is crucial, and fast membership testing is required. DictionariesKey-value lookups (faster than lists)Perfect for mapping keys to values, offering fast access times and efficient insertion and deletion operations. ...
链接:https://leetcode-cn.com/problems/remove-all-adjacent-duplicates-in-string python # 1047.删除所有相邻的重复字符 class Solution: def removeDuplicates(self,s: str) -> str: """ 借助辅助栈,同则出栈,否则入栈,最后拼接字符返回,时间O(n), 空间最坏O(n) ...
# Finding duplicates in census_Bcensus_B_duplicates = census_B[census_B.index.isin(duplicate_rows)]# Finding new rows in census_Bcensus_B_new = census_B[~census_B.index.isin(duplicate_rows)]# Link the DataFrames!full...
# Finding duplicates in census_B census_B_duplicates = census_B[census_B.index.isin(duplicate_rows)] # Finding new rows in census_B census_B_new = census_B[~census_B.index.isin(duplicate_rows)] # Link the DataFrames! full_census = census_A.append(census_B_new)至此,我们结束对数据清...