deffind_all_occurrences_list_comprehension(string,sub_string):positions=[iforiinrange(len(string)-len(sub_string)+1)ifstring[i:i+len(sub_string)].lower()==sub_string.lower()]returnpositions# 示例text="Hello, hello, hello, World!"sub_text="hello"positions=find_all_occurrences_list_comprehe...
下面是一个代码示例,演示了如何使用列表推导式查找字符串中多次出现的位置: deffind_all_occurrences(string,sub_string):return[indexforindex,charinenumerate(string)ifchar==sub_string]# 示例用法string="abracadabra"sub_string="a"occurrences=find_all_occurrences(string,sub_string)print(occurrences)# 输出 [...
实例代码如下：>>>string='hello world'>>>'m'notinstringTrue>>>'e'notinstringFalse原文地址：py...
Return the number of non-overlapping occurrences of substring sub in the range [start, end]. Optional arguments start and end are interpreted as in slice notation. str.decode([encoding[, errors]]) 解码 Decodes the string using the codec registered for encoding. encoding defaults to the default...
Python Find String in List usingcount() We can also usecount()function to get the number of occurrences of a string in the list. If its output is 0, the string is not present in the list. l1=['A','B','C','D','A','A','C']s='A'count=l1.count(s)ifcount>0:print(f'{...
To check if a string starts or ends with a pattern: if re.match(r"^Search", text): print("Starts with 'Search'") if re.search(r"patterns.$", text): print("Ends with 'patterns.'") 4. Finding All Matches To find all occurrences of a pattern in a string: all_matches = re.fin...
306 """ 307 return s.rsplit(sep, maxsplit) 308 309 # Join fields with optional separator 310 def join(words, sep = ' '): 311 """join(list [,sep]) -> string 312 313 Return a string composed of the words in list, with 314 intervening occurrences of sep. The default separator ...
a nice string representation of the object. | If the argument is a string, the return value is the same object. | | Method resolution order: | str | basestring | object | | Methods defined here: | | __add__(...) | x.__add__(y) <==> x+y | | __contains__(...) | x...
sub) Help on function sub in module re: sub(pattern, repl, string, count=0, flags=0) Return the string obtained by replacing the leftmost non-overlapping occurrences of the pattern in string by the replacement repl. repl can be either a string or a callable; if a string, backslash ...
| Return the number of non-overlapping occurrences of substring sub in | string S[start:end]. Optional arguments start and end are | interpreted as in slice notation. | | encode(...) | S.encode(encoding='utf-8', errors='strict') -> bytes ...