在 Python 中,我们可以通过re模块来使用正则表达式。 importredeffind_numbers_in_string(s):# 使用正则表达式查找所有数字numbers=re.findall(r'\d+',s)returnnumbers sample_string="在2023年,我计划去三亚旅游,费用大约5000元。"found_numbers=find_numbers_in_string(sample_string)print(found_numbers) 1. 2...
👋一、findall()函数的基本用法 🎁findall()函数的基本语法是：re.findall(pattern, string, flags=0)。其中，pattern是正则表达式的模式和规则，string是要搜索的字符串，flags是标志位，用于控制正则表达式的匹配方式，如是否区分大小写等。📘下面是一个简单的例子，演示了如何使用findall()函数从一个字符串...
import re str1 = "Python4you123" str_num = [] str_num = re.findall('[0-9]', str1) print(str_num) # 输出:['4', '1', '2', '3'] 使用nums_from_string 模块 创建一个包含所有数字字符串格式的列表,使用 in 检查字符串中的字符是否包含在列表中。 import nums_from_string str1 ...
importre# 定义一个包含数字的字符串text="There are 123 apples and 456 oranges in the basket."# 使用正则表达式提取数字numbers=re.findall(r'\d+',text)print(numbers) 1. 2. 3. 4. 5. 6. 7. 8. 9. 在上面的代码中,我们使用re.findall()函数来查找字符串中的所有匹配项,并将其存储在一个...
string_pattern = '[a-z]+' result = re.findall(string_pattern, input_string) print(result) print(type(result)) In the following code: The “re” module is imported at the start of the program. The input string containing numbers and alphabets is initialized in the program. ...
```pythonimport retext = "There are 2 cats and 3 dogs in the house."numbers = re.findall(r'\d+', text)print(numbers) # Output: ['2', '3']```在这个例子中，我们使用了re.findall()函数来查找字符串text中的所有数字。正则表达式模式'\d+'用于匹配一个或多个数字。最后，findall函数...
int("25") is not an integer literal because the integer value is created from a string.When you write large numbers by hand, you typically group digits into groups of three separated by a comma or a decimal point. The number 1,000,000 is a lot easier to read than 1000000....
*Numbers(数字)*String(字符串)*List(列表)*Tuple(元组)*Dictionary(字典) 三、 Python数字(Number) Python数字类型用于存储数值数值类型是不允许改变的,这就意味着如果改变数字类型的值,将重新分配内存空间 代码语言:javascript 代码运行次数:0 运行 AI代码解释 ...
str.find(sub[, start[, end]])在字符串中查找sub,找到后返回位置,没找到返回-1. Return the lowest index in the string where substring sub is found, such that sub is contained in the range [start, end]. Optional arguments start and end are interpreted as in slice notation. Return -1 if...
import retext = "The numbers are 139-626 and 123456."# 贪婪模式pattern_greedy = re.compile(r'\d+')matches_greedy = pattern_greedy.findall(text)print(matches_greedy)# 输出: ['139', '626', '123456']# 非贪婪模式pattern_lazy = re.compile(r'\d+?')matches_lazy = pattern_lazy.findal...