使用数学方法 import mathdef check_odd_even(num):if int(num/2) == num/2:return"偶数"else:return"奇数"while 1: data = int(input("请输入一个数: ")) print("判断结果为：", check_odd_even(data))输出结果：使用数学方法来判断一个数是否为偶数，如果该数除以 2 的结果是整数，则该数...
Pictorial Presentation of Even Numbers: Pictorial Presentation of Odd Numbers: Sample Solution: Python Code: # Prompt the user to enter a number and convert the input to an integernum=int(input("Enter a number: "))# Calculate the remainder when the number is divided by 2mod=num%2# Check ...
text="判断",command=check_odd_even)check_button.pack()# 运行主循环root.mainloop()odd 代表奇数,...
print(number, “是奇数”) check_even_or_odd(7) # 输出:7 是奇数 check_even_or_odd(12) # 输出:12 是偶数 “` 上述代码定义了一个`check_even_or_odd`函数,它接受一个参数`number`表示要判断的数字。函数内部使用取余运算判断`number`除以2的余数,如果余数为0,则打印出”是偶数”的提示;否则,打印...
Check if a Number is Even or Odd in Python Python provides several ways to achieve this task. Let us learnsome important methods. Method 1. Use the Modulo Operator (%) The most common approach to check if a number is even or odd in Python is using themodulo operator (%). The modulo...
defis_number_even(num): """Function to check if number is even or odd""" return"Even"ifnum%2==0else"Odd" NUM=5 print(f"The number {NUM} is {is_number_even(NUM)}") 通过这段代码,我们添加了一个模块和函数docstring,在结尾处添加了一个...
defcheck_even_odd(number):ifnumber%2==0:return"偶数"else:return"奇数" 1. 2. 3. 4. 5. 在这个例子中,check_even_odd函数接收一个参数number。如果number能被2整除,函数将返回“偶数”,否则返回“奇数”。 2.2 多条件的示例 假设我们需要一个函数来判断一个考试成绩等级: ...
# Python program to check if the input number is odd or even. # A number is even if division by 2 gives a remainder of 0. # If the remainder is 1, it is an odd number. num = int(input("Enter a number: ")) if (num % 2) == 0: print("{0} is Even".format(num)) else...
We will learn how to check if any given number is even or odd using different techniques, using the subtraction method and using the modulo operator method.
[9] == sign)) def checker(digit): global count, mark, digits # Check which button clicked if digit == 1 and digit in digits: digits.remove(digit) ##player1 will play if the value of count is even and for odd player2 will play if count % 2 == 0: mark = 'X' panels[digit]...