使用数学方法 import mathdef check_odd_even(num):if int(num/2) == num/2:return"偶数"else:return"奇数"while 1: data = int(input("请输入一个数: ")) print("判断结果为：", check_odd_even(data))输出结果：使用数学方法来判断一个数是否为偶数，如果该数除以 2 的结果是整数，则该数...
importtkinterastk# 定义奇偶数判断函数defcheck_odd_even():try:number=int(entry.get())# 获取用户...
print(number, “是奇数”) check_even_or_odd(7) # 输出:7 是奇数 check_even_or_odd(12) # 输出:12 是偶数 “` 上述代码定义了一个`check_even_or_odd`函数,它接受一个参数`number`表示要判断的数字。函数内部使用取余运算判断`number`除以2的余数,如果余数为0,则打印出”是偶数”的提示;否则,打印...
例如,我们需要一个函数来判断一个数字是奇数还是偶数: defcheck_even_odd(number):ifnumber%2==0:return"偶数"else:return"奇数" 1. 2. 3. 4. 5. 在这个例子中,check_even_odd函数接收一个参数number。如果number能被2整除,函数将返回“偶数”,否则返回“奇数”。 2.2 多条件的示例 假设我们需要一个函数...
If the remainder is not zero, the number is odd. Source Code # Python program to check if the input number is odd or even. # A number is even if division by 2 gives a remainder of 0. # If the remainder is 1, it is an odd number. num = int(input("Enter a number: ")) if...
even=Image.new(origin.mode,(width//2,height//2))forxinrange(width):foryinrange(height):# 根据 x + y 的奇偶性质分离到不同的图片if(x+y)%2==0:odd.putpixel((x//2,y//2),origin.getpixel((x,y)))else:even.putpixel((x//2,y//2),origin.getpixel((x,y)))odd.show()even.show...
We will learn how to check if any given number is even or odd using different techniques, using the subtraction method and using the modulo operator method.
complex_transformation = list(map(lambda x: x**2 if x % 2 == 0 else x + 5, range(5))) print(complex_transformation) # Applies different transformations based on even-odd condition Working With Object Oriented Programming 1. Defining a Class Creating a class: class Wizard: def __init_...
defis_number_even(num): """Function to check if number is even or odd""" return"Even"ifnum%2==0else"Odd" NUM=5 print(f"The number {NUM} is {is_number_even(NUM)}") 通过这段代码,我们添加了一个模块和函数docstring,在结尾处添加了一个...
if i % 2 == 0: # even pi += 4 / k else: # odd pi -= 4 / k k += 2 return pi # Settings order=6 N = 1_000 items = range(N) # Serial run result = [batch_process_function(row, order, None) for row in items] ...