# Prompt the user to enter a number and convert the input to an integernum=int(input("Enter a number: "))# Calculate the remainder when the number is divided by 2mod=num%2# Check if the remainder is greater than 0, indicating an odd numberifmod>0:# Print a message indicating that ...
The most common approach to check if a number is even or odd in Python is using themodulo operator (%). The modulo operator returns the remainder after division. An even number is evenly divisible by 2 with no remainder, while an odd number leaves a remainder of 1 when divided by 2. ...
# Python program to check if the input number is odd or even. # A number is even if division by 2 gives a remainder of 0. # If the remainder is 1, it is an odd number. num = int(input("Enter a number: ")) if (num % 2) == 0: print("{0} is Even".format(num)) else...
import time def check_even(numbers): even = [] for num in numbers: if num % 2 == 0: even.append(num*num) return evenif __name__ == '__main__': m1 = memory_profiler.memory_usage() t1 = time.clock() cubes = check_even(range(100000000)) t2 = time.clock() m2 = memory_p...
def is_even(num): if num & 1 == 0: return True else: return False def is_odd(num): if num & 1 == 1: return True else: return False # 测试示例 print(is_even(4)) # 输出:True print(is_odd(7)) # 输出:True “` 3. 使用divmod函数判断:divmod函数可以同时返回一个数除以另一...
Check your installed dependenciesforsecurity vulnerabilities:$ pipenv check Install a local setup.py into your virtual environment/Pipfile:$ pipenv install-e.Use a lower-level pip command:$ pipenv run pip freezeCommands:check ChecksforPyUp Safety security vulnerabilities and againstPEP508markers providedi...
We will learn how to check if any given number is even or odd using different techniques, using the subtraction method and using the modulo operator method.
print("Number of hard links: ", stat_info.st_nlink)print("Owner User ID: ", stat_info.st_uid)print("Group ID: ", stat_info.st_gid)print("File Size: ", stat_info.st_size) 但等等,这还不是全部!我们可以使用os.path()模块来提取更多的元数据。例如,我们可以使用它来确定文件是否是符号...
def check_number(number): if number > 0: return "Positive" elif number == 0: return "Zero" return "Negative" print(check_number(1)) # Positive ▍38、使用sorted()检查2个字符串是否为相同 def check_if_anagram(first_word, second_word): first_word = first_word.lower() second_word = ...
(i)# Check if each digit in the current number 'i' is even (divisible by 2)if(int(s[0])%2==0)and(int(s[1])%2==0)and(int(s[2])%2==0):# If all digits are even, append the string representation of 'i' to the 'items' listitems.append(s)# Join the elements in the ...