Python中的enumerate()方法可以同时获取列表中元素的值和索引。例如，我们有一个列表a=[1,2,3,4,5]，想要遍历列表并查找数字3在列表中的索引，可以使用以下代码：'''a=[1,2,3,4,5]for index,value in enumerate(a):if value==3:print("The index of 3 is",index)break '''输出结果为"The index ...
'数学', '英语'] scores = [[]] * 5 for row, name in enumerate(names): print('请输入%s的成绩' % name) scores[row] = [0] * 3 #变为不再嵌套 for col, subj in enumerate(subjs): scores[row][col] = float(input(subj + ': ')) print(scores)if __name__ == '__main...
import PySimpleGUI as sgimport timemylist = [1,2,3,4,5,6,7,8] fori, iteminenumerate(mylist): sg.one_line_progress_meter( This is my progress meter! , i+1, len(mylist), -key- ) time.sleep(1) PySimpleGUI 应用程序中的进度条 项目...
list = map(lambda x: x * 2, list) list = map(lambda x,y:x*y,lista,listb) products = [a * b for a, b in zip(list1, list2)] # or just use numpy array # matrix addition: list(map(lambda x:x+2,[2,3,4])) np.array([2,3,4])+2 # element by element multiply of p...
fori,iteminenumerate(mylist): print(item) time.sleep(1) progress_bar.UpdateBar(i + 1)window.close 没错,在 Python 脚本中使用进度条只需要几行代码,一点也不复杂。有了进度条,以后也不用再猜测脚本运行地怎么样了。 点击标题可跳转 1、Python自动化操作Excel、Word、PPT、PDF工具 ...
python list Share Improve this question Follow asked Mar 9, 2020 at 10:29 user3424575 10177 bronze badges Add a comment 1 Answer Sorted by: 3 Here's one possible way to achieve this using a nested list comprehension: new_lst = [[e for j, e in enumerate(lst[i]) if [i, j...
Python enumerate() 函数 # 列表,元祖,字符串 seasons = ['Spring', 'Summer', 'Fall', 'Winter'] print(list(enumerate(seasons))) for i in enumerate(seasons): print(i[0],i[1]) 1. 2. 3. 4. 5. str = 'spring' print(list(enumerate(str))) ...
forindex, yearinenumerate(year_list): # 使用add_trace绘制轨迹 fig.add_trace(go.Scatter( x=[-20,40], y=np.full(2, len(year_list) - index), mode='lines', line_color='white')) fig.add_trace(go.Scatter( x=array_dict[f'x_{year}'], ...
Python内置的enumerate函数可以把一个list变成索引-元素对,这样就可以在for循环中同时迭代索引和元素本身: >>>fori, valueinenumerate(['A','B','C']): ...print(i, value) ... 0 A1B2 C 上面的for循环里,同时引用了两个变量,在Python里是很常见的,比如下面的代码: ...
(shape_piece.shape)] for i, line in enumerate(list_of_shapes): row = list(line) for j, column in enumerate(row): if column == '0': positions.append((shape_piece.x + j, shape_piece.y + i)) for p, block_pos in enumerate(positions): positions[p] = (block_pos[0] - 2, ...